The cat has gone 7/16 of the way across the yard. How much farther does it have to go to reach the gate?

Mathematics

2 answers:

snow_tiger [21]3 years ago

7 0

9/16 ways to go...unless the gate is closer you didn't really say where the gate is

uysha [10]3 years ago

3 0

7+ ? = 16
7+ 9 =16
that cat needs to go 9/16 farther

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How do i solve for x?

kirza4 [7]

Answer:

x = 6

Step-by-step explanation:

We can see that the the 32 degree angle plus the equation (9x + 4) is equal to 90 degrees.

We know this because the bottom line is a 180 degree angle, and we can see on the other side that it is a right angle.

If we were to turn that into an equation it would like like this:

(9x + 4) + 32 = 90

Now you just have to solve for x.

9x + 4 + 32 = 90

Combine like terms:

9x + 36 = 90

Subtract 36 from both sides

9x = 54

divide both sides by 9

x = 6

and you are left with the answer.

6 0

2 years ago

Please help...

alexandr402 [8]

Sure. From those choices, the only one that makes sense is that he
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number of times.

I have a hunch that even for only 60 trials, such a great discrepancy between
theory and experiment is beginning to suggest that the cubie is loaded. But
you really can't say. You just have to keep trying and watch how the numbers
add up.

3 0

2 years ago

I need help with questions #7 and #8 plz

katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

$c^2 = a^2 + b^2 - 2ab \cos C$

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

We use the law of cosines to find C.

$18^2 = 12^2 + 16^2 - 2(12)(16) \cos C$