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poizon [28]
3 years ago
14

Steve has 50 notebooks with red covers but only 40 notebooks with blue covers. If he uses up 6 notebooks with red covers and 4 w

ith blue covers each month, in how many months will he have the same number of red as blue notebooks?
Mathematics
1 answer:
Akimi4 [234]3 years ago
6 0

Answer:

5 months

Step-by-step explanation:

The first thing to do is to obtain the difference between the two numbers of colored books, 50 and 40.

50 - 40 = 10 notebooks.

We need to calculate how long it will take for this difference to disappear, noting that Steve uses more of the red cover notebooks every month. The difference on a monthly basis is

6 - 4 = 2 notebooks per month

So, now the number of months will be gotten from;

Number of months = \frac{Total Difference}{Monthly Difference}

Number of months = \frac{10}{2} = 5 months

We can check for this,

After 5 months, Steve would have used 5 × 6 red cover notebooks = 30

and 5 × 4 blue cover notebooks = 20

The remaining number of books will be:

RED: 50 - 30 = 20 red cover notebooks

BLUE: 40 - 20 = 20 blue cover notebooks.

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This problem is very difficult to imagine without the figure. However I dug up on other sources and I think I found the correct figure to work with (see the attached pic).

 

We can see that in the figure, the hexagon is inscribing the pentagon. What is meant here to be lines of reflection simply means lines of symmetry. If we take on the hexagon alone, there are a lot of lines of symmetry. We can create the line intersecting E & B and the figure would still be symmetrical on both sides or D & A, F & C and etc. So there are a lot for hexagon alone.

 

However in this case, our lines of symmetry is made limited by the presence of the pentagon. If we slice the pentagon into two, the only line of symmetry we could create would be the line intersecting O and the median of LM. Other lines would not create a symmetrical half.

 

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