For number 19:
"at least 150" means either 150 ≤ ? or ? ≥ 150
plus 3 so +3x
The answer would be 150 ≤ 100 + 3x
Number 20:
A is at -2.5. The inverse is the opposite so 2.5
The answers are (2 1/2, 10) and (3, 12)
//I just took the test and these were the answers
ANSWER
The correct answers are option B and D.

EXPLANATION
The given expression is

We need to simplify the above expression in order to determine the option that is equivalent to it.
The least common denominator for the last two fractions is 3.
This implies that,

We simplify to obtain,

This further simplifies to give us,

This is option B.
When we further factor -4, we get,

This is option D.
Answer:
y = 3x - 2
Step-by-step explanation:
y +8 = 3 (x + 2)
y + 8 = 3x + 6
y = 3x - 2
Answer: a) 83, b) 28, c) 14, d) 28.
Step-by-step explanation:
Since we have given that
n(B) = 69
n(Br)=90
n(C)=59
n(B∩Br)=28
n(B∩C)=20
n(Br∩C)=24
n(B∩Br∩C)=10
a) How many of the 269 college students do not like any of these three vegetables?
n(B∪Br∪C)=n(B)+n(Br)+n(C)-n(B∩Br)-n(B∩C)-n(Br∩C)+n(B∩Br∩C)
n(B∪Br∪C)=
So, n(B∪Br∪C)'=269-n(B∪Br∪C)=269-156=83
b) How many like broccoli only?
n(only Br)=n(Br) -(n(B∩Br)+n(Br∩C)+n(B∩Br∩C))
n(only Br)=
c) How many like broccoli AND cauliflower but not Brussels sprouts?
n(Br∩C-B)=n(Br∩C)-n(B∩Br∩C)
n(Br∩C-B)=
d) How many like neither Brussels sprouts nor cauliflower?
n(B'∪C')=n(only Br)= 28
Hence, a) 83, b) 28, c) 14, d) 28.