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Serjik [45]
3 years ago
15

4.5x-7=20 what is the right answer some help please

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
6 0

Answer:

x=6

Step-by-step explanation:

zloy xaker [14]3 years ago
4 0

Answer:

\boxed{\bold{x=6}}

Step By Step Explanation:

Multiply Both Sides By 10

\bold{4.5x\cdot \:10-7\cdot \:10=20\cdot \:10}

Simplify

\boxed{\bold{45x-70=200}}

Add 70 To Both Sides

\bold{45x-70+70=200+70}

Simplify

\bold{45x=270}

Divide Both Sides By 45

\bold{\frac{45x}{45}=\frac{270}{45}}

Simplify

\bold{x=6}

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In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408

#Define Y:

Y~(11.04,5.7408)

P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291

Hence, the probability of 12 or fewer is 0.8291

b. The  probability that 5 or more fish were caught.

#Using normal approximation:

P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above P(X\geq 5)=0.9968 and a ,P(X\leq 12)=0.7291

P(5\leq X\leq 120\approx P(4.5\leq Y\leq  12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259

Hence, the probability of between 5 and 12 is 0.7259

4 0
3 years ago
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