Area of rectangular board = length (inches) x width (inches) = 12" x 16" = 192 in²
Area of the border is given as 128 in²
Adding the area of the board and the border gives (192 + 128)in² = 320 in²
Set this up as the algebraic equation (x + 12)(x + 16) = 320 and solve for x:
Remember to use the FOIL method, which is multiplying the terms in the order of first, outer, inner, last.
x² + 12x + 16x + 192 = 320
x² + 28x + 192 - 320 = 0
x² + 28x - 128 = 0
solve for the two x values:
(x + 32)(x - 4) = 0, and knowing we only need the positive x value
x = 4 or 4 inches is the width of the border
Answer:
x=1 or -1/2
Step-by-step explanation:
The value of x is 1 or -1/2
Answer:
least to greatest : 14/9 , sqrt 7, sqrt 13, sqrt 40, 4^3
Step-by-step explanation:
Well nine times 199 is 1,791but im not sure if thats what its asking
Answer: area= 4.7
Area=pi*r^2=3.14*1.5=4.71=4.7 (nearest tenth)
