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ella [17]
3 years ago
7

The major difference between a template and another document is in _____.

Computers and Technology
1 answer:
VikaD [51]3 years ago
4 0

Answer:

I think that how its saved

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Write a program to convert a fraction to a decimal. Have your program ask for the numerator first, then the denominator. Make su
Anton [14]
<h2>Answer:</h2>

import java.util.Scanner;

public class FractionToDecimal {

   public static void main(String[] args) {

       Scanner input = new Scanner(System.in);

       

       System.out.println("Please enter the numerator");

       double numerator = input.nextDouble();

       System.out.println("Please enter the denominator");

       double denominator = input.nextDouble();

       

       if(denominator == 0){

           System.err.println("ERROR - Cannot divide by zero.");

       }

       else {

           System.out.println("The result is " + (numerator/denominator));

       }

       

   }

   

}

<h2>Explanation:</h2>

// import the Scanner class to allow for user input

import java.util.Scanner;

// 1. Declare a class

public class FractionToDecimal {

   // 2. Write the main method

   public static void main(String[] args) {

       

       // 3. Create an object of the Scanner class called <em>input</em>

       Scanner input = new Scanner(System.in);

       

       // 4. Prompt the user to supply the numerator

       System.out.println("Please enter the numerator");

       

       // 5. Declare and initialize a variable <em>numerator </em>to hold the numerator

       // supplied by the user.

       // The numerator is of type double since the program does not

       // specify any. With a double both integer and floating point numbers

       // will be supported.

       double numerator = input.nextDouble();

       

       // 6. Prompt the user to enter the denominator

       System.out.println("Please enter the denominator");

       // 7. Declare and initialize a variable <em>denominator </em>to hold the

       // denominator supplied by the user.

       // The denominator is also of type double since the program does not

       // specify any. With a double, both integer and floating point numbers

       // will be supported.

       double denominator = input.nextDouble();

       // 8. Check if the denominator is or is not zero.

       // if it is zero, display an error message        

       if(denominator == 0){

           System.err.println("ERROR - Cannot divide by zero.");

       }

       // if it is not zero, then print out the result of the division

       else {

           System.out.println("The result is " + (numerator/denominator));

       }

       

   }                       // end of main method

   

}                            // end of class declaration

Please Note:

The code above has been written in Java.

The explanation segment contains comments to explain every line of the code.

But a few things are still worth noting;

i. Dividing the numerator by the denominator will convert a fraction to decimal.

ii. The object of the Scanner class <em>input </em> is used to get the inputs (numerator and denominator) from the user. Since the inputs are going to be integers or doubles, the nextDouble() method of the the Scanner class is used.

iii. If the denominator is zero, an error message will be displayed. I have used the System.err.println() method for that rather than the regular System.out.println() method. The difference is that the former will print out the error text in red color.

iv. Notice also that the else statement in the code will perform the division and also print out the result of the division along side with some text.

<em>Hope this helps!</em>

3 0
3 years ago
Write a program that continually prompts the user for an integer input until input is entered that is less than 0. Each input th
professor190 [17]

Answer:

Following are the program in the C++ Programming Language:

#include <iostream>//header file

using namespace std;//namespane

//set main method

int main() {  

int a[100]; //set integer type array variable

int value, i = 0; //set integer variables

cout<<"Enter less than 0 to exit:"<<endl; //message for exit

cout<<"Enter the integer numbers:"<<endl; //message to enter numbers

do{ //set do while

cin>>value; //get input from the user

a[i++] = value; //append elements in array

}while(value>=0);

i--;  

cout<<"\nArray are:"<<endl;//message for array

for(int k = 0;k<i;k++){ //set for loop

cout<<a[k]<<" "; //print array

}

return 0;

}

<u>Output</u>:

Enter less than 0 to exit:

Enter the integer numbers:

1

2

3

4

5

-1

Array are:

1 2 3 4 5

Explanation:

Here, we set the integer data type main method "main()" and inside it:

  • we set integer type array variable with index value 100.
  • we set two integer type variable "value" and "i" initialize value 0.
  • we set the do-while loop in which we get the input from the user and and append in the array and pass condition if the value is greater then equal to 0.
  • Finally, set for loop and print the elements of an array.

 

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Harry needs to use a type of graph in a spreadsheet to show variations in data over a specific period. What type of graph or cha
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Bar graph!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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You're an administrator for a large corporation and you are responsible for deploying computers often and quickly. What server d
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What time is spellrd the same forwards and backwards​
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12:21 is the correct answer
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