21 not sure but you can do it
Step-by-step explanation:
Actual graph for this problem is attached below
m∠TUV = 167°
m∠TUL = (x + 11)°
m∠LUV = (11x)°
m∠TUV=
m∠TUL+
m∠LUV
now plug in the angles for each
m∠TUV=
m∠TUL+
m∠LUV

solve the equation for x

Subtract 11 from both sides

divide both sides by 12
x=13
m∠TUL = (x + 11)°
m∠TUL = (13+ 11)°
= (24)°
answer:
24°
The nearest degree would be 40
Answer:
<h3>4</h3>
Step-by-step explanation:
