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san4es73 [151]
3 years ago
7

Which linear inequality is graphed in the figure

Mathematics
1 answer:
Maslowich3 years ago
5 0
Some states authorize a to make healthcare decisions ------- for patients who can't make them because they're incapacitated. O a) healthcare proxy b) living will O c) durable power of attorney O d) do-not-resuscitate orderغ
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Triangle ABC has points at A(2, 0), B(−1, 3), and C(4, 5). After undergoing a transformation, its new points are A'(6, 0), B'(3,
djverab [1.8K]

Answer:C

Step-by-step explanation:

6 0
3 years ago
Adam and.his dad share the cost of the meal in the ratio of 2:3 adams dad pays 52.50 what is the to cost of the meal?
larisa86 [58]
Adam pays for 2/5 of the meal so his father pays for 3/5

3/5  = 52.50
1/5 = 52.50 / 3 = 17.50

so cost of the meal = 5 * 17.50 = $87.50


7 0
3 years ago
What is the answer to the equation X=3-(3x6)+2?
dolphi86 [110]
  x =  3 - (3×6) + 2.        We perform the operation in the bracket first.

  x =  3 - 18 + 2

  x =  -15 + 2 = 2 -15 = -13

 x  = -13
4 0
3 years ago
What is the volume of the pyramid?
Ivenika [448]

Answer:

The Great Pyramid of Giza/Volume

<h2>2.6 million m3</h2>

Step-by-step explanation:

The great pyramid of Giza

5 0
3 years ago
A turtle lives in a garden and a hedgehog lives in the woods. They leave their homes at the same time walk toward each other and
Jlenok [28]

Based on the calculations, the distance between the garden and the woods is equal to 383 meters.

<h3>How to calculate the distance.</h3>

First of all, we would assign a variable to the different speeds of the turtle and hedgehog as follows:

  • Let the turtle's speed be S₁.
  • Let the hedgehog's speed be S₂.

Mathematically, distance is given by this formula:

Distance = speed × time

Translating the word problem into an algebraic expression, we have;

If they both meet in 5 hours:

D = (S₁ + S₂) × 5  

D = 5S₁ + 5S₂      ......equation 1.

Turtle's speed is 10 meters per hour slower than the hedgehog:

S₁ = S₂ - 10    .....equation 2.

If the turtle had left home 4.5 hours earlier than the hedgehog had left his home:

9.5S₁ + 5S₂ = D + 150    .....equation 3.

Substituting enq. 2 into eqn. 1, we have:

D = 5(S₂ - 10) + 5S₂

D = 5S₂ - 50 + 5S₂

D = 10S₂ - 50      .....equation 4.

Equating eqn. 3 and eqn. 4, we have:

10S₂ - 50 = 9.5(S₂ - 10) + 5S₂ - 150

10S₂ - 50 = 9.5S₂ - 95 + 5S₂ - 150

10S₂ - 50 = 14.5S₂ - 245

14.5S₂ - 10S₂ = 245 - 50

4.5S₂ = 195

S₂ = 195/4.5

S₂ = 43.3 m/h.

Now, we can find the distnace:

D = 10S₂ - 50

D = 10(43.3) - 50

D = 433 - 50

D = 383 meters.

Learn more about distance here: brainly.com/question/10545161

4 0
2 years ago
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