Question

A softball is tossed into the air upward from a first floor balcony. The distance of the ball 14 +32t -16t^2 above the ground at any time is given by the function, the softball above the ground (in feet) and t is the time (in seconds) what was the maximum in feet, after t was thrown? where h() is the height of

Answer 1

You can either find the roots of the quadratic formula using the quadratic formula two find the halfway point or you can use the formula t=-b/2a.  Both of the two methods gives you the axis of symmetry (the t value for the vertex).
I will use the second method since I don't like using the quadratic formula.
t=-32/(2x-16)
t=1 second
After you find the t value for the axis of symmetry, you plug it into the formula of the graph to find the height.
h=-16+32+14
h=30 feet