A softball is tossed into the air upward from a first floor balcony. The distance of the ball 14 +32t -16t^2 above the ground at
any time is given by the function, the softball above the ground (in feet) and t is the time (in seconds) what was the maximum in feet, after t was thrown? where h() is the height of
1 answer:
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Answer:
Step-by-step explanation:
we have
This is the equation of a vertical parabola open upward
The vertex is a minimum
The equation of a vertical parabola in vertex form is equal to
where
(h,k) is the vertex
Convert the given function to vertex form
Factor the leading coefficient
Complete the square
Rewrite as perfect squares
------> equation in vertex form
The vertex is the point (2,6)