Answer:
The answer I have to say would be D. Please correct me if I am wrong but I am positive with my answer!
Step-by-step explanation:
The length would be 9 and the width would be 3
The tangent line to a curve is the one that coincides with the curve at a point and with the same derivative, that is, the same degree of variation.
We have then:
y = 5x-x²
Deriving:
y '= 5-2x
In point (1, 4)
The slope is:
y (1) '= 5-2 * (1)
y (1) '= 3
The equation of the line will be:
y-f (a) = f '(a) (x-a)
We have then:
y-4 = 3 (x-1)
Rewriting:
y = 3x-3 + 4
y = 3x + 1
Answer:
the tangent line to the parabola at the point (1, 4) is
y = 3x + 1
the slope m is
m = 3
28 × 1 which equals to "28"
14 × 2 which also equals to "28"
7 × 4 which also equals to "28"
The answer to this question is letter C) By segment addition, DC plus BD is equal to BC. Point D is located at the middle of segment BC. Therefore BC is just equal to BD plus DC.
<span>Now we can prove BC2 = BA2+CA2 by using the Pythagorean theorem.</span>