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White raven [17]
3 years ago
6

Consider the following system:

Mathematics
2 answers:
Goryan [66]3 years ago
4 0
You did not include the choices. However, I answered one that just included them. I've included the possible answers below and then the correct answers. 

<span>A multiple of Equation 1. 
B. The sum of Equation 1 and Equation 2 
C. An equation that replaces only the coefficient of x with the sum of the coefficients of x in Equation 1 and Equation 2. 
D. An equation that replaces only the coefficient of y with the sum of the coefficients of y in Equation 1 and Equation 2. 
E. The sum of a multiple of Equation 1 and Equation 2.

</span>A, B and E.

Adding and multiplying the terms allow them to keep working. However, you must make sure that each variable is changed each time. Not just one as in C and D. 
Shkiper50 [21]3 years ago
4 0

You did not include the choices. However, I answered one that just included them. I've included the possible answers below and then the correct answers. 


A multiple of Equation 1. 

B. The sum of Equation 1 and Equation 2 

C. An equation that replaces only the coefficient of x with the sum of the coefficients of x in Equation 1 and Equation 2. 

D. An equation that replaces only the coefficient of y with the sum of the coefficients of y in Equation 1 and Equation 2. 

E. The sum of a multiple of Equation 1 and Equation 2.


A, B and E.


Adding and multiplying the terms allow them to keep working. However, you must make sure that each variable is changed each time. Not just one as in C and D. 


Read more on Brainly.com - brainly.com/question/9662635#readmore

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A movie theater has a 24​-foot-high screen located 6 feet above your eye level. If you sit x feet back from the​ screen, your vi
pantera1 [17]

Answer:

The viewing angles are as follows:

For x=5 feet, θ = 0.529 radians

For x=10 feet, θ = 0.708 radians

For x=15 feet, θ = 0.726 radians

For x=20 feet, θ = 0.691 radians

For x=25 feet, θ = 0.640 radians

Step-by-step explanation:

The viewing angle is given as:

θ = tan⁻¹(30/x) - tan⁻¹ (6/x)

where x is the distance between you and the screen.

The question is asking us to find the viewing angle θ at various distances. The distance value needs to be substituted in the above equation in place of x. So,

<u>For x=5 feet:</u>

θ = tan⁻¹(30/5) - tan⁻¹ (6/5)

  = 1.4056 - 0.8761

θ = 0.529 radians

<u>For x = 10 feet:</u>

θ = tan⁻¹(30/10) - tan⁻¹ (6/10)

  = 1.249 - 0.540

θ = 0.708 radians

<u>For x = 15 feet:</u>

θ = tan⁻¹(30/15) - tan⁻¹ (6/15)

  = 1.107 - 0.380

θ = 0.726 radians

<u>For x = 20 feet:</u>

θ = tan⁻¹(30/20) - tan⁻¹ (6/20)

  = 0.983 - 0.291

θ = 0.691 radians

<u>For x = 25 feet:</u>

θ = tan⁻¹(30/25) - tan⁻¹ (6/25)

  = 0.876 - 0.235

θ = 0.640 radians

5 0
3 years ago
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