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Tanya [424]
3 years ago
11

Use repeated subtraction to divide 95/10

Mathematics
1 answer:
ziro4ka [17]3 years ago
3 0
Well, I don't know how to use repeated subtraction, but I do know how to divide 95/10:

95 ÷ 10 = 9 r 5 (the "r" represents remainder)
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Simplify (4ab^2)^3<br><br> Any help is appreciated
Pie

Answer:

64a^{3} b^{6}

Step-by-step explanation:

1) Distribute the exponent outside of the parentheses to the terms inside the parentheses. In this case, multiply the 3 outside the parentheses with the exponent of each of the terms inside:

(4ab^{2} )^3

4^{3} · a^{3} · b^{6}

2) The variables are fine - you can't simplify them further. All you need to do now is multiply the 4^{3} out. Remember that it's kind of like asking, "what is 4 × 4 ×4?"

4 · 4 · 4 · a^{3} · b^{6}

16 · 4 · a^{3} · b^{6}

64a^{3} b^{6}

Therefore, 64a^{3} b^{6} is the answer.

3 0
3 years ago
HELP PLEASE !! .................................................................................................................
myrzilka [38]

Answer:

15

Step-by-step explanation:

Substitute a and b then

Follow PEMDAS

Hope this helps! :)

5 0
3 years ago
Read 2 more answers
What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?
lbvjy [14]

Answer:

The equation of the quadratic graph is f(x)= - (1/8) (x-3)^2 + 3 (second option)

Step-by-step explanation:

Focus: F=(3,1)=(xf, yf)→xf=3, yf=1

Directrix: y=5 (horizontal line), then the axis of the parabola is vertical, and the equation has the form:

f(x)=[1 / (4p)] (x-h)^2+k

where Vertex: V=(h,k)

The directix y=5 must intercept the axis of the parabola at the point (3,5), and the vertex is the midpoint between this point and the focus:

Vertex is the midpoint between (3,5) and (3,1):

h=(3+3)/2→h=6/2→h=3

k=(5+1)/2→k=6/2→k=3

Vertex: V=(h,k)→V=(3,3)

p=yf-k→p=1-3→p=-2

Replacing the values in the equation:

f(x)= [ 1 / (4(-2)) ] (x-3)^2 + 3

f(x)=[ 1 / (-8) ] (x-3)^2 + 3

f(x)= - (1/8) (x-3)^2 + 3

4 0
3 years ago
Evaluate: (8y+5) -2z; if y =3 and z =9
iVinArrow [24]

Answer:

11

Step-by-step explanation:

(8y + 5) - 2z

y = 3, z = 9

Let's plug in the given values.

(8(3) + 5) - 2(9)

First let's multiply.

(24 + 5) - 18

Now simplify within the parentheses.

29 - 18

Subtract.

11

This is your answer.

Hope this helps!

5 0
3 years ago
The midpoint of \overline{\text{AB}}AB is M(-6, -4)M(−6,−4). If the coordinates of AA are (-4, -3)(−4,−3), what are the coordina
valentina_108 [34]

Answer:

The coordinates of B is (-8,-5).

Step-by-step explanation:

The midpoint of line AB is M. The coordinate of M is (-6,-4).

The coordinates of A is (-4,-3)

We need to find the mid point of B.

If M(x,y) is the midpoint of the coordinates (x₁,y₁) and (x₂,y₂). The mid point theorem is used as follows :

M(x,y)=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})

Let the mid point of B is (x₂,y₂). Put (x,y) = (-6,-4), (x₁,y₁) = (-4,-3).

(-6,-4)=(\dfrac{-4+x_2}{2},\dfrac{-3+y_2}{2})\\\\\dfrac{-4+x_2}{2}=-6\ \text{and}\ \dfrac{-3+y_2}{2}=-4\\\\-4+x_2=-12\ \text{and}\ -3+y_2=-8\\\\x_2=-12+4\ \text{and}\ y_2=-8+3\\\\x_2=-8\ \text{and}\ y_2=-5

So, the coordinates of B is (-8,-5).

6 0
3 years ago
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