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yulyashka [42]
3 years ago
13

Please help me thanks!

Mathematics
2 answers:
stepladder [879]3 years ago
8 0

Answer:

If you use 3.14 for pi

1278.1 ft^2

Using the pi button on the calculator

1278.8 ft^2

Step-by-step explanation:

First find the volume of the cylinder

V = pi r^2 h where r is the radius and h is the height of the cylinder

V = pi ( 5.8) ^2 ( 8.9)

V = pi *33.64 * 8.9

V = 299.396 pi

The find the volume of the cone

V= 1/3 pi r^2h

The height of the cone is  18.5- 8.9 =9.6

V= 1/3 ( pi ) ( 5.8)^2 ( 9.6)

V= 1/3 ( pi ) 33.64 ( 9.6)

V = 107.648 pi

Add the two volumes together

299.396 pi + 107.648 pi

407.044 pi

If you use 3.14 for pi

1278.11816 ft^2

Rounding to the nearest tenth

1278.1 ft^2

Using the pi button on the calculator

1278.76644

Rounding to the nearest tenth

1278.8 ft^2

Nitella [24]3 years ago
3 0

Answer:

1278.8 ft^3

Step-by-step explanation:

radius of cylinder = r = 5.8 ft

height of cylinder = h = 8.9 ft

radius of cone = r = 5.8 ft

height of cone = H - h = 18.5 ft - 8.9 ft = 9.6 ft

volume = volume of cylinder + volume of cone

V = (pi)(r^2)h + (1/3)(pi)(r^2)(H - h)

V = (3.14159)(5.8^2 ft^2)(8.9 ft) + (1/3)(3.14159)(5.8^2 ft^2)(9.6 ft)

V = 1278.8 ft^3

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Arianna is packing scented candles and candle holders into gift boxes. She has 84 candles and 48 holders, and each box must cont
pav-90 [236]

Answer:

Step-by-step explanation:

If she has 84 candles and 48 holders, we can write out the factors of both values as shown

For candles

84 = 2×2×3×7

84 = 12×7

For 48

48 = 2×2×2×2×3

48 = (2×2)×(2×2×3)

48 = 4×12

48 = 12×4

From both factors, we can are that 12 common to both of them. This means that the maximum number of gift boxes Ariana can pack is 12

The other factors will give the amount of scented candles and candle holders that each box will have. This means that each box will have 7scented candles and 4 holders.

7 0
3 years ago
If c is the hypotenuse of a right triangle,find the missing side. If necessary, round to the nearest hundredth. c=sqrt(155), b=s
Lunna [17]
A^2 + 31 = 155  - I squared each of b and c for those numbers
a^2 = 155 - 31
a^2 = 124
a = 4 * sqrt(31)
6 0
4 years ago
An object in shm oscillates with a period of 4.0s and an amplitude of 11 cm . part a how long does the object take to move from
Alika [10]
If the Amplitud is 11×2=22cm and the wave was in shm then we can get the wavelength as 11×2=22s.
From the wave equation, 

v=fλ Where v⇒speed
                    f⇒frequency and 
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And we know that; 
f=1/T
f = 1/4 =0.25 Hz
∴v = 0.25 ×22 = 5.5 cm/s

Since we know know the speed of the object we can get its time it takes from (0-6.5) cm.

v = fλ = λ/T

∴T = λ/v
     = 6.5/5.5
      = 1 2/11
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The time taken for the object <span>to move from x = 0.0 cm to x = 6.5 cm is </span>1.181818s

5 0
4 years ago
Determine the approximate value of side A.<br>​
Sveta_85 [38]

Answer:

A should be 40 if not sorry

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Help please! ill mark brainliest!
jenyasd209 [6]

Answer:

The answer is 90

Step-by-step explanation:

When HI=GH

Then m<G=m<I= 45

m<H=180-(45+45)=90

If you need any explanation in it or anything on math you can communicate with me on Whats on this number +201557831028 or in email or face or anything

4 0
3 years ago
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