Answer:
4
Step-by-step explanation:
Answer:
Plate Area = PI * radius^2
Plate Area = 3.14159 * 6 * 6
Plate Area = 113.09724 square inches
Plate Area = 113.1 square inches (rounded)
Step-by-step explanation:
9514 1404 393
Answer:
[[274][895][136]]
Step-by-step explanation:
Starting with the middle row, we need a product of two single-digit numbers that is between 53-1 = 52 and 53-9 = 44. Possible products are 5×9=45 and 6×8=48. This means the number in the middle position in the left column must be 8 or 5.
The middle number in the left column cannot be 5, because we must be able to get -5 by subtracting that number from a sum that is at least 3 = 1+2. So, the middle number in the left column is 8, the other two numbers in that column are 1 and 2, and the other two numbers in the middle row are 5 and 9.
There is no product of single-digit numbers that is 30-1 = 29, so the upper left number must be 2, and the bottom left number must be 1. The other two numbers on the top row must be 4 and 7, so that row's equation is 2+4×7=30.
The only remaining digits are 3 and 6. In order to have -3 on the bottom row, the equation there must be 1×3-6 = -3. Then the middle digit must be divisible by 3, so must be 9.
Our solution is ...
row 1: 2 + 7 × 4 = 30
row 2: 8 + 9 × 5 = 53
row 3: 1 × 3 - 6 = -3
And that makes the column equations be ...
col 1: 2 - 8 + 1 = -5
col 2: 7 + 9 / 3 = 10
col 3: 4 × 5 - 6 = 14
The equation of the regression line is : Ŷ = 0.8571+0.8878X
Given the set of points :
(1, 2), (4,4), (9,9)
X axis : ___ Y axis
1 ___________2
1 ___________2 4 __________ 4
1 ___________2 4 __________ 4 9 __________ 9
The regression line associated could be obtained using technology such as excel, linear regression solvers or a graphing calculator.
Using technology :
Input the values of X and Y into their appropriate column and plot :
The regression equation obtained is :
Ŷ = 0.8571 + 0.8878X
Where :
Ŷ = predicted value of Y(dependent variable)
X = Independent variable
Slope = 0.8878
Intercept = 0.8571
The regression plot is attached below
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