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Hunter-Best [27]
3 years ago
14

If a horizontal line segment is 5 units in length,What is the endpoint for the line segment?

Mathematics
1 answer:
IceJOKER [234]3 years ago
4 0

Answer: -3,7

Step-by-step explanation:

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Please help ill do anything and no links
alekssr [168]

Answer:

5. Obtuse angle and angle measurement- 130

6. Obtuse angle and angle measurement- 110

Step-by-step explanation:

If you look at the protractor you can see the numbers and if its right of the 90 degrees than its acute if its left of the 90 degrees than its obtuse. If its 90 degrees exactly then its a right angle. And you look at the numbers below the line to find the measurement and look where the line is exactly, then thats your measurement. Hope this helped!

7 0
2 years ago
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Express as a trinomial (2x+8)(x-3)
Luden [163]

Answer:

\huge\boxed{(2x+8)(x-3)=2x^2+2x-24}

Step-by-step explanation:

\text{Use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(2x+8)(x-3)=(2x)(x)+(2x)(-3)+(8)(x)+(8)(-3)\\\\=2x^2-6x+8x-24\qquad\text{combine like terms}\\\\=2x^2+(-6x+8x)-24\\\\=2x^2+2x-24

8 0
3 years ago
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20 EASY POINTS PLUS BRAINLIEST IF YOU ANSWER THIS QUESTION
GarryVolchara [31]

Mark me as Brainliest Please

4 0
3 years ago
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Allisa [31]

Answer:

3)

Step-by-step explanation:

4 0
3 years ago
Solve:<br><br><img src="https://tex.z-dn.net/?f=%5Cunderset%7Bx%5Crightarrow~3%7D%7B%5Clim%7D~%5Cdfrac%7B2x%5E2-18%7D%7Bx%5E2-3x
vodomira [7]

Hello, please consider the following.

\displaystyle \lim_{x\rightarrow3}~\dfrac{2x^2-18}{x^2-3x} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x^2-3^2)}{x(x-3)} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x-3)(x+3)}{x(x-3)} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x+3)}{x} \\ \\ \\=\dfrac{2(3+3)}{3}\\ \\ \\=\dfrac{2*3*2}{3} =\Large \boxed{\sf \bf \ 4 \ }

Thank you

8 0
3 years ago
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