you sight a rock climber on a cliff at a 32° angle of elevation. your eye level is 5.5 feet above the ground and you are 1000 fe et from the base of the cliff. what is the approximate height of the rock climber from the ground?
1 answer:
Answer:
630 feets
Step-by-step explanation:
From the triangle attached :
Using trigonometry, the height h, which is the height of climber to your eye level :
Tan θ = opposite / Adjacent
Tan 32 = h / 1000
h = tan 32 * 1000
h = 0.6248693 * 1000
h = 624.86935
Height from the ground :
624.86935 + 5.5
= 630.369 feets
= 630 feet
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