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chubhunter [2.5K]
2 years ago
14

Explain why a magnet from your refrigerator could not be used to life something as heavy as a car ?

Physics
1 answer:
sesenic [268]2 years ago
8 0

Answer:

Explanation:

because it wouldnt connect

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When time is measured in​ days, the decay constant for a particular radioactive isotope is 0.16. Determine the time required for
san4es73 [151]

Answer:

The time take is  t = 1.3964 \ days

Explanation:

From the question we are told that

    The decay constant is  \lambda  = 0.16

     The percentage fall is  c =  0.80

The equation for radioactive decay is mathematically represented as

               N(t) =  N_o  * e^{- \lambda t  }

Where is N(t) is the new amount of the new the isotope while N_o is the original

At initial  N_o =  100%  = 1

At N(t ) =  80%  = 0.80  

       0.80 =  1 * e^{- 0.16 t }

=>     -0.223 =  -0.16 t

=>     t = 1.3964 \ days

5 0
3 years ago
Read 2 more answers
Calculate the period of a satellite orbiting the Moon, 98 kmkm above the Moon's surface. Ignore effects of the Earth. The radius
beks73 [17]

Answer:

3.6*10^18s

Explanation:

To find the period of the satellite

We need to apply kephler's third law

Which is

MP² = (4π²/G) d³

d=semi-major axis which is the distance from center of moon = 98km+1740km = 1838km

where M= mass of the moon = 7.3x10^22kg

P=period

G=newtonian gravatational constant= 6.67x10^-11

To find the Period solve for P

P = √[(4π²/G M)xd³]

P=√(4 π²/6.67x10^-22*7.3x10^22kg) x (1.838x10^6m)³]

= 3.6*10^18s

6 0
3 years ago
How does the resistance change as you add bulbs to a series circuit?
Ronch [10]
The resistance is increased when more and more bulbs are added to the circuit.
7 0
2 years ago
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Two elements in Period 4 that are most similar to Cobalt?
lisabon 2012 [21]
Iron and nickel are the elements most similar to cobalt
5 0
3 years ago
The x component of vector is -27.3 m and the y component is +43.6 m. (a) What is the magnitude of ? (b) What is the angle betwee
lara [203]

Answer:51.44 units

Explanation:

Given

x component of vector is -27.3\hat{i}

y component of vector is 43.6\hat{j}

so position vector is

r=-27.3\hat{i}+43.6\hat{j}

Magnitude of vector is

|r|=\sqrt{27.3^2+43.6^2}

|r|=\sqrt{2646.25}

|r|=51.44 units

Direction

tan\theta =\frac{43.6}{-27.3}=-1.597

vector is in 2nd quadrant thus

180-\theta =57.94

\theta =122.06^{\circ}

4 0
3 years ago
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