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3 years ago

Why is an iron core needed in an electromagnet?

1 answer:

4 0

An iron core is needed in an electromagnet because it serves to increase the magnetic field created. It has a ferromagnetic properties. An electromagnet is essentially just a battery attached to a coil of wire wrapped around a metalcore.

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How are metals produced? Does this process use sustainable methods? Explain

Marat540 [252]

Certain metals such as steel,aluminium follow sustainable methods but some does not.

Explanation:

Metal production means conversion of a raw material, such as a metallic ore, to a final form which can be used for some commercial or industrial purpose. In some cases, metal production gives few steps since the metal already occurs in an elemental form in nature.

Sustainable manufacturing is the creation of manufactured products through economic processes that minimize negative environmental impacts while conserving energy and natural resources.

Steel is a uniquely sustainable material because Steel is truly recyclable and is truly recycled.

Aluminum poses no danger of environmental toxicity therefore, secondary aluminum production from recycling scrap has the potential to significantly reduce greenhouse gas emissions.

But some metals production does not follow subsequent methods.

7 0

3 years ago

Why does an astronaut have to use electrical medium to talk in the space

Evgen [1.6K]

Explanation:

because there is no air to communicate

8 0

3 years ago

Read 2 more answers

A ball is kicked horizontally with a speed of 5.0 ms-1 from the roof of a house 3 m high. When will the ball hit the ground?

Burka [1]

Answer:

the time taken for the ball to hit the ground is 0.424 s

Explanation:

Given;

velocity of the ball, u = 5 m/s

height of the house which the ball was kicked, h = 3m

Apply kinematic equation;

h = ut + ¹/₂gt²

where;

h is height above ground

u is velocity

g is acceleration due to gravity

t is the time taken for the ball to hit the ground

Substitute the given values and solve for t

3 = 5t + ¹/₂(9.8)t²

3 = 5t + 4.9t²

4.9t² + 5t -3 = 0

a = 4.9, b = 5, c = -3

Solve for t using formula method

$t = \frac{-5 +/-\sqrt{5^2-4(4.9*-3)}}{2(4.9)} = \frac{-5+/-(9.154)}{9.8} \\\\t = \frac{-5+9.154}{9.8} \ or \ \frac{-5-9.154}{9.8} \\\\t = \frac{4.154}{9.8} \ or \ \frac{-14.154}{9.8} \\\\t = 0.424 \ sec \ or -1.444 \ sec\\\\Thus, t = 0.424 \ sec$

5 0

3 years ago

Which of the following devices can be used to measure force?

Novay_Z [31]

Answer:

Explanation:

d.All of the above

7 0

3 years ago

A thick, spherical shell made of solid metal has an inner radius a = 0.18 m and an outer radius b = 0.46 m, and is initially unc

KonstantinChe [14]

(a) $E(r) = \frac{q}{4\pi \epsilon_0 r^2}$

We can solve the different part of the problem by using Gauss theorem.

Considering a Gaussian spherical surface with radius r<a (inside the shell), we can write:

$E(r) \cdot 4\pi r^2 = \frac{q}{\epsilon_0}$

where q is the charge contained in the spherical surface, so

$q=5.00 C$

Solving for E(r), we find the expression of the field for r<a:

$E(r) = \frac{q}{4\pi \epsilon_0 r^2}$

(b) 0

The electric field strength in the region a < r < b is zero. This is due to the fact that the charge +q placed at the center of the shell induces an opposite charge -q on the inner surface of the shell (r=a), while the outer surface of the shell (r=b) will acquire a net charge of +q.

So, if we use Gauss theorem for the region a < r < b, we get

$E(r) \cdot 4\pi r^2 = \frac{q'}{\epsilon_0}$

however, the charge q' contained in the Gaussian sphere of radius r is now the sum of the charge at the centre (+q) and the charge induced on the inner surface of the shell (-q), so

q' = + q - q = 0

And so we find

E(r) = 0

(c) $E(r) = \frac{q}{4\pi \epsilon_0 r^2}$

We can use again Gauss theorem:

$E(r) \cdot 4\pi r^2 = \frac{q'}{\epsilon_0}$ (1)

where this time r > b (outside the shell), so the gaussian surface this time contained:

- the charge +q at the centre

- the inner surface, with a charge of -q

- the outer surface, with a charge of +q

So the net charge is

q' = +q -q +q = +q