Answer:
v1=18.46m/s
v2=29.8cm/s
Explanation:
We know that

the equation of the motion is

we can calculate w by using

Hence, we have that

the speed will be

hope this helps!
Answer:
<h2>Derived quantities are based on fundamental quantities, and they can be given in terms of fundamental quantities.</h2>
<h3>Fundamental quantities are the base quantities of a unit system, and they are defined independent of the other quantities. </h3>
Explanation:
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Sample Response: No image will be formed because the rays will not converge to or diverge from a common point.
Answer:
h≅ 58 m
Explanation:
GIVEN:
mass of rocket M= 62,000 kg
fuel consumption rate = 150 kg/s
velocity of exhaust gases v= 6000 m/s
Now thrust = rate of fuel consumption×velocity of exhaust gases
=6000 × 150 = 900000 N
now to need calculate time t = amount of fuel consumed÷ rate
= 744/150= 4.96 sec
applying newton's law
M×a= thrust - Mg
62000 a=900000- 62000×9.8
acceleration a= 4.71 m/s^2
its height after 744 kg of its total fuel load has been consumed


h= 58.012 m
h≅ 58 m