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NeTakaya
3 years ago
11

Combustion is an example of ______ to_______ energy conversion.

Physics
1 answer:
Viefleur [7K]3 years ago
7 0
Combustion is and example of an oxidation reaction to burning/high energy conversion.
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Block B has mass 6.00 kg and sits at rest on a horizontal, frictionless surface. Block A has mass 2.50 kg and sits at rest on to
zzz [600]

Answer:

Explanation:

Block A sits on block B and force is applied on block A . Block A will experience two forces 1) force P and 2 )  friction force in opposite direction of motion . Block B will experience one force that is force of friction in the direction of motion .

Let force on block A be P . friction force on it will be equal to kinetic friction, that is μ mg , where μ is coefficient of friction and m is mass of block A

friction force = .4 x 2.5 x 9.8

= 9.8 N

net force on block A = P - 9.8

acceleration = ( P - 9.8 ) / 2.5

force on block B = 9.8

acceleration = force / mass

= 9.8 / 6

for common acceleration

( P - 9.8 ) / 2.5  = 9.8 / 6

( P - 9.8 ) / 2.5 = 1.63333

P = 13.88 N .

4 0
3 years ago
Which types of waves requires matter to carry energy? electromagnetic waves only mechanical waves only electromagnetic and mecha
gogolik [260]

Answer: Mechanical waves

Explanation:

Mechanical waves require a medium in order to transport their energy from one location to another. A sound wave is an example of a mechanical wave. Sound waves are incapable of traveling through a vacuum.

7 0
3 years ago
Read 2 more answers
What are some indicators of energy transformations?
Annette [7]

Explanation:

Contact, vision, sound, flavor, and smell are all markers of energy transformations. The most basic example would be when we notice something has begun to pass through vision. Whenever an entity accelerates or slows down, energy is constantly transformed.

5 0
3 years ago
How to do this question
Anna71 [15]

Answer:

(a) 10 m/s

(b) 22.4 m/s

Explanation:

(a) Draw a free body diagram of the car when it is at the top of the loop.  There are two forces: weight force mg pulling down, and normal force N pushing down.

Sum of forces in the centripetal direction (towards the center):

∑F = ma

mg + N = mv²/r

At minimum speed, the normal force is 0.

mg = mv²/r

g = v²/r

v = √(gr)

v = √(10 m/s² × 10.0 m)

v = 10 m/s

(b) Energy is conserved.

Initial kinetic energy + initial potential energy = final kinetic energy

½ mv₀² + mgh = ½ mv²

v₀² + 2gh = v²

(10 m/s)² + 2 (10 m/s²) (20.0 m) = v²

v = 22.4 m/s

4 0
3 years ago
What is the electric field 4.0 m from the center of the terminal of a Van de Graaff with a 7.10 mC charge, noting that the field
Jobisdone [24]

Answer:

3984875 N/C

Explanation:

Applying,

E = kq/r².................. Equation 1

Where E = Electric field, q = charge, r = distance, k = coulomb's constant.

From the question,

Given: q = 7.10 mC = 0.0071 C, r = 4.0 m

Constant: k = 8.98×10⁹ Nm²/C²

Substitute these values into equation 1

E = 0.0071(8.98×10⁹)/4²

E = 3984875 N/C

Hence the electric field is 3984875 N/C

5 0
3 years ago
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