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olganol [36]
3 years ago
15

Which translation vectors could have been used for the pair of figures ?

Mathematics
2 answers:
valina [46]3 years ago
8 0
Base on the question where as asking to state the translation vectors could have been used for the pair of figures, base on my research, I would say  that the answer would be <span>arrow pointing to the right. I hope you are satisfied with my answer and feel free to ask for more if you have questions</span>
soldier1979 [14.2K]3 years ago
3 0

Answer:

According to the numbering below, the correct options are 3 and 6.

Step-by-step explanation:

Let us number the figures in the following way,

1        2

3       4

5       6

We are required to find the translation vectors that can be used for the pair of figures given.

It is known that a translating vector moves the image to any direction.

As no information is given as to which figure is translated to obtain the other. So, we assume that translation can be applied to both.

So, the vectors that can be used for the pair of figures would be 3 and 6 as they will translate the below figure to the place of above and the above figure to the place of below respectively.

Hence, vectors 3 and 6 could be used.

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Step-by-step explanation:

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Find the volume of the figure. Round your answer to the nearest tenth if necessary. Use 3.14 for T.
seraphim [82]

Answer:

\boxed{ \rm \: Volume_{(Cylinder)} \approx \: 461.6  \:  {m}^{3} } \rm (rounded \: to \: nearest \: tenth)

Step-by-step explanation:

Given dimensions:

  • Radius of the cylinder = 7 metres
  • Height of the cylinder = 3 metres

Given value of π :

  • π = 3.14

To find:

  • The Volume of the cylinder

Solution:

Here, we'll need to use the formulae of the volume of cylinder,to find it's volume.Its actually like a savior while solving these type of questions.

\pink{\star}\boxed{\rm \: Volume_{(Cylinder)} = \pi{r} {}^{2} h}\pink{\star}

where,

  • π = 3.14
  • r² = (radius)²
  • h = height

Plug/substitute them onto the formulae,then simplify it using PEMDAS.

  • [We'll substitute the value of π later]

\rm \: Volume_{(Cylinder)} = \pi(7) {}^{2}  \times 3

\rm \: Volume_{(Cylinder)} = \pi(49)(3)

\rm \: Volume_{(Cylinder)} = 147\pi \:

  • Now substitute the value of π.

\rm \: Volume_{(Cylinder)} = 147 \times 3.14

\rm \: Volume_{(Cylinder)} = 461.58 \:  {m}^{3}

\boxed{\rm \: Volume_{(Cylinder)} \approx \: 461.6  \:  {m}^{3}} \rm (rounded \: to \: nearest \: tenth) \:

<u>Hence, we can conclude that:</u>

The volume of the cylinder is approximately

461.6 m³.

\rule{225pt}{2pt}

3 0
3 years ago
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