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2 years ago

What is the distance between (3, -8) and (0, -2)

2 answers:

7 0

You would use the distance formula sqrt( (x2 - x1)^2 + (y2 - y1)^2)
sqrt( (0-3)^2 + (-2--8)^2)
sqrt( (-3)^2 + (6)^2 )
sqrt( 9 + 36 )
sqrt(45)
simplified 3sqrt5
decimal 6.71

faltersainse [42]2 years ago

3 0

The answer is 3√5. You use the distance formula: √((x2-x1)^2+(y2-y1)^2)

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Please help 2х -3y =18

siniylev [52]

Answer:

x = 3(6 + y)/2

Step-by-step explanation:

Solving for x

Add 3y to both sides.

2x = 18 + 3y

Divide both sides by 2.

x = 18 + 3y/2

Factor out the common term 3.

x = 3(6 + y)/2

3 0

2 years ago

What is the value of x? Enter your answer in the box. mm Triangle V T K with segment T Y such that Y is on segment V K, between

lapo4ka [179]

Answer:

VK = x = 98 mm

Step-by-step explanation:

TY is the bisector of angle T, so it divides segments of the triangle proportionally. That is, ...

VY/VT = KY/KT

VY = VT·KY/KT = (57 mm)·68/192.2 = 30 mm

Then

VK = VY + YK = 30 mm + 68 mm

VK = 98 mm

5 0

3 years ago

Read 2 more answers

What is the relationship between 1.0 and 0.1

dexar [7]

1/10×1.0=0.1

answer: C

5 0

3 years ago

Find the value of f(9) and g(-9) if f(×) = -7×-9 and g(×) = 6×3-23×

Vlada [557]

Answer:

f(9)= -72

g(-9)= 225

Step-by-step explanation:

First put the original equation

f(x)=-7x-9

Next plug in the number f(9)

f(9)=-7(9)-9

After multiply -7(9) which gets you -63

f(9)=-63-9

Then subtract -63-9 which gets you -72

f(9)=-72

-----------------------------------------------------------

First put the original

g(x)=6x3-23x

Next plug in the number g(-9)

g(-9)=6x3-23(-9)

After multiply 6x3 which gives you 18 then multiply -23(-9)

g(-9)=18+207

then add 18+207 which gives you 225

g(-9)=225

8 0

3 years ago

The yield of orange trees is reduced if they are planted too close together. If there are 30 trees per acre, each tree produces

Tanya [424]

Answer:

5 more than 30 trees should be planted, for a total of 40 trees per acre.

Step-by-step explanation:

Let x be the number of trees beyond 30 that are planted on the acre

The number of oranges produced = Oranges(x) = (number of trees) (yield per tree)

We are given that For each additional tree in the acre, the yield is reduced by 7 oranges per tree

So, number of oranges produced = $(30 + x)(400 -10x)$

= $12000 -300x+400x-10x^2$

= $12000 + 100x-10x^2$

The derivative Oranges'(x) = 100-20x

Substitute first derivative equals to 0

$100-20x =0$

$x=5$

Using the second derivative test,

Oranges"(x) = -20

20 is negative,

So, this is the case of maximum.

Thus, 5 more than 30 trees should be planted, for a total of 40 trees per acre.

4 0

3 years ago