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vova2212 [387]
3 years ago
6

Two machines, Y and Z, work at constant rates producing identical items. Machine Y produces 3 items in the same time Machine Z p

roduces 2 items. If machine Y takes 9 minutes to produce a batch of items, how many minutes does it take for machine Z to produce the same number of items?
A. 6
B. 9
C. 9 1/2
D. 12
E. 13 1/2
Mathematics
1 answer:
umka2103 [35]3 years ago
8 0

Answer:

E. 13 1/2

Step-by-step explanation:

As two machine Y and Z at constant rate is in 3/2 .So if a machine Y is working 3/2 then the rate of other machine Z is 2/3 time take. Y take 9 minutes.So, 9 = (2/3) the time

so T = 9 * 3 / 2

T = 13.5

So option E is true.  

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Joyce can type 60 words in five minutes. Robert can type 48 words in six minutes words who type at the faster and how many words
erik [133]

Answer:

joyce

Step-by-step explanation:

60/5 =12

48/6 =8

6 0
3 years ago
Paul opens a savings account with $350. He saves $150 per month. After how many months will Paul have $2150 in the account?​
Debora [2.8K]

Answer:

12 months

Step-by-step explanation:

2150-350=1800

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3 0
3 years ago
5(y-4)=7(2y+1)<br>I need the answer​
8_murik_8 [283]

Answer: y = -3

Move all terms containing y to the left, all other terms to the right

<u>Add -14y to each side of the equation</u>

<u></u>-20 + 5y + -14y = 7 + 14y + -14y<u></u>

<u></u>

<u>Combine like terms: 5y + -14y = -9y </u>

<u></u>-20 + -9y = 7 + 14y + -14y<u></u>

<u></u>

<u>Combine like terms: 14y + -14y = 0 </u>

<u></u>-20 + -9y = 7 + 0\\-20 + -9y = 7<u></u>

<u></u>

<u>Add '20' to each side of the equation</u>

<u></u>-20 + 20 + -9y = 7 + 20<u></u>

<u></u>

<u>Combine like terms: -20 + 20 = 0 </u>

<u></u>0 + -9y = 7 + 20\\-9y = 7 + 20<u></u>

<u></u>

<u>Combine like terms: 7 + 20 = 27 </u>

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<u></u>

<u>Divide each side by -9</u>

<u></u>-9y/9=27/-9\\y=-3<u></u>

8 0
4 years ago
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snow_lady [41]

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Estimate answer is C.

6 0
3 years ago
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The expression 5,430,900 is written in standard notation.
MA_775_DIABLO [31]
Its false, standard notation would have an exponent. 

4 0
3 years ago
Read 2 more answers
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