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romanna [79]
3 years ago
6

Please help mefor this questions please help me​

Mathematics
1 answer:
Harrizon [31]3 years ago
7 0

And.. the question is...?

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Karen is hosting a pizza party for herself and 29 guests. She wants to order enough pizzas so that each person gets more than 1/
shutvik [7]
29 guests+<span>Karen------------------ > 30 persons

</span><span>1/5*30=6 pizzas
2/3*30=20 pizzas
x=</span><span>quantities of pizza
x>6
x<20
   6< x<20
</span><span>quantities of pizza (7,8,9,10,11,12,13,14,15,16,17,18,19)
</span>13 different quantities of pizza
7 0
3 years ago
I need help please. I need the the discount and selling price. Thank you
Sati [7]
The discount is $1,880 and the selling price is $21,620, make sure to put the dollar sign to make sure you know what the number means
7 0
2 years ago
1.The length of a ship model is 3% of the length of the actual ship. The model is 1.5 M long. How long is the actual ship? ____M
Vilka [71]
We have to find 100% of the number. We can use proportion to get it
3% -----------1.5m
100% -------- x
crossmultiply now
3*x=1.5*100
3x=150      /:3 divide both sides by 3
x=50m

2. Similar situation
40% ------------1000
100% -----------x
crossmultiply
40*x=100*1000
40x=100000      /:40
x=2500 - its the answer
8 0
3 years ago
Help me please I haven't been able to figure this one out and I am not that very good at Stem and leaf plots.
klio [65]

Answer:

1 l 0 0 5 5 5

2 l

3 l 7

4 l

5 l

6 l 5

7 l 0

8 l 68

9 l

Step-by-step explanation:

1 l 0 0 5 5 5 =10,10,15,15,15

And so on.

4 0
3 years ago
Find domain of y=rad20-6x
Evgesh-ka [11]
Domain, on an "even root" context, means, an even root cannot have a negative radicand, since  say for example \bf \sqrt{-25}\ne -5\qquad why?\implies (-5)(-5)=25

so... you end up with an "imaginary value"

so... for the case of 20-6x
"x", the domain, or INPUT
can afford to have any value, so long it doesn't make the radicand negative

to check for that, let us make the expression to 0, and see what is "x" then

\bf 20-6x=0\implies 20=6x\implies \cfrac{20}{6}=x\implies \cfrac{10}{3}=x

now, if "x" is 10/3, let's see \bf \sqrt{20-6\left( \frac{10}{3} \right)}\implies \sqrt{20-20}\implies \sqrt{0}\implies 0

now, 0 is not negative, so the radicand is golden

BUT, if "x" has a value higher than 10/3, the radicand turns negative
for example  \bf x=\frac{11}{3}&#10;\\\\\\&#10;&#10;\sqrt{20-6\left( \frac{11}{3} \right)}\implies \sqrt{20-22}\implies \sqrt{-2}

so.. that's not a good value for "x"

thus, the domain, or values "x" can safely take on, are all real numbers from 10/3 onwards, or to infinity if you wish
5 0
3 years ago
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