Ask question

Ask question

All categories

Diano4ka-milaya [45]

2 years ago

7

A section of the crust moves under another section of crust without changing the land

1 answer:

Alex17521 [72]2 years ago

7 0

Answer:

D

Step-by-step explanation:

You might be interested in

Which phrase SIgnals a compare and-contrast text structure O as a result betore long for this reason on the other hand

Shalnov [3]

Answer:

D. On the other hand.

Step-by-step explanation:

As a result, before long, and for this reason would be cause and effect. On the other hand is the only remaining option.

7 0

2 years ago

In a department store the owner paid $15 for 1kg of sugar.The owner marked the price up by 10% for the customers.How much dose h

oee [108]

First, we need to figure out 10% of fifteen.

So, we multiple 15 by 10% (or 0.1 in simpler terms).

That gives us 1.5, which is our mark-up price.

So, finally we add the markup price to the original price to obtain the selling price.

1.5 + 15 = 16.5

The owner charges $16.50 for 1kg of sugar!

5 0

3 years ago

Find the value for the side marked below.

olga55 [171]

Answer:

Solution given:

angle : 80°

hypotenuse:y=?

opposite=21

we have

Sin 80= $\frac{opposite} {hypotenuse}=\frac{21}{y}$

doing crisscrossed multiplication

we get

y= $\frac{21}{Sin 80°}$

<u>y=21.32</u>

6 0

2 years ago

Kay [80]

Answer:

$\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}$

$4.535 \leq \sigma^2 \leq 7.602$

Now we just take square root on both sides of the interval and we got:

$2.2 \leq \sigma \leq 2.8$

And the best option would be:

A. 2.2 < σ < 2.8

Step-by-step explanation:

Information provided

$\bar X=32.1$ represent the sample mean

$\mu$ population mean

s=2.4 represent the sample standard deviation

n=83 represent the sample size

Confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom are given by:

$df=n-1=83-1=82$

The Confidence is given by 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , the critical values for this case are:

$\chi^2_{\alpha/2}=62.132$

$\chi^2_{1- \alpha/2}=104.139$

And replacing into the formula for the interval we got:

$\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}$

$4.535 \leq \sigma^2 \leq 7.602$

Now we just take square root on both sides of the interval and we got:

$2.2 \leq \sigma \leq 2.8$

And the best option would be:

A. 2.2 < σ < 2.8

3 0

3 years ago

Please Find the distance between the two points rounding to the nearest tenth (if necessary).

Sphinxa [80]

Answer:

10.29 u

Step-by-step explanation:

<u>Given :- </u>

Two points (7,4) and (-2,9) is given to us.

And we need to find out the distance between the two points . So , here we can use the distance formula to find out the distance. As,

$:\implies$ D = √{(x2-x1)² + (y2-y1)²}

$:\implies$ D =√[ (7+2)² +(9-4)²]

$:\implies$ D =√[ 9² +5²]

$:\implies$ D =√[ 81 +25]

$:\implies$ D = 10.29

<h3>Hence the distance between the two points is 10.29 units .</h3>

8 0

2 years ago

Read 2 more answers