BRAINLIET TO THE FIRST.....AND PLZZ HURRY.....
2 answers:
Answer:
142.4 units^3
Step-by-step explanation:
We use the same formula for volume as for a cone
V = 1/3 pi r^2 h
V = 1/3 pi (4)^2 ( 8.5)
= 1/3 pi (16)(8.5)
Letting pi = 3.14
=142.34666667
Rounding to the nearest tenth
= 142.4
Formula for the volume of a cone: V = 1/3 x pi x r^2 x h
Since this is a right cone, the height is given as 8.5 and the radius is 4.
V = 1/3 x pi x 4^2 x 8.5
V = 1/3 x pi x 16 x 8.5
V = 1/3 x pi x 136
V = 45 1/3 pi
V = 142.4 cubic units
Hope this helps!
You might be interested in
True I think cause it’s divided by 5
Answer:
h = 76
Step-by-step explanation:
2 + h - 48 = 30
h + 2 - 48 = 30
h - 46 = 30
h - 46 + 46 = 30 + 46
h = 76
Answer:
WHAT? ok ok so
Step-by-step explanation:
GF = GH
<F = <H
<E=<G
or
<EGF = <HGJ
answer
<span>e) AAS
</span><span>d) ASA</span>

Step-by-step explanation:


<em>Prologarithmize both parts of the equation:</em>

<u><em> Divide both parts of the equation by 2:</em></u>

