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Dimas [21]
3 years ago
12

Write the relation as a set of ordered pairs.

Mathematics
2 answers:
Vlad [161]3 years ago
8 0
I think it letter C
Negative 2 so it means -2
Then to 4 so
(-2,4)
Then 0 to 0. So
(-2,4), (0,0),
Then 2 to 4
So
{(-2,4),(0,0),(2,4)}
atroni [7]3 years ago
3 0
Not 100% sure but I think it’s b. hope this helps!
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1/4+3/8 and show work, please!!
gregori [183]

Answer:

The answer is 5/8

Step-by-step explanation:

Step 1 : Convert both fractions so they have the same denominator (bottom number in the fraction.)

1/4 = 2/8

So now were dealing with :

2/8 + 3/8 = ?

Step 2 : Add the numerators together to get the numerator for our answer.

2 + 3 = 5

When adding two fractions with the same denominator the denominator stays the same, so our answer is 5/8.

Hope this helps, please mark brainliest. :) Have a nice day.

7 0
3 years ago
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kow [346]

Answer:

m=17/40  \frac{17}{40}

Step-by-step explanation:

So you 5/7m - 1/7 = 9/56 \frac{5}{7}m - \frac{1}{7} = \frac{9}{56}

You Simplify both sides Then

well I Don´t know I hope this helped u, I tried ^^¨

8 0
4 years ago
Put the following equation of a line into slope-intercept form, simplifying all fractions. 3x + 6y = 42​
kodGreya [7K]
Y = 1/2 +7
Can u thank, rate and make me brainliest, have a good day
5 0
3 years ago
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Which statement is true about point F? a.F is the midpoint of AA' because bisects AA'. b.F is the midpoint of EG because AA' bis
Dimas [21]

Answer:

The correct option is;

a. F is the midpoint of \overline{AA'} because line \overline{EG} bisects \overline{AA'}

Step-by-step explanation:

Here, since we have that the triangle is reflected across EG therefore the location of the point F which is along EG bisects the line \overline{AA'} as the  dimensions of the line from A to F must be equal to the dimension of the line that extends from A' to F

Therefore the point F is the midpoint of \overline{AA'} because line \overline{EG} bisects \overline{AA'}.

7 0
3 years ago
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kobusy [5.1K]
Look at the picture.

I hope this helps!

5 0
3 years ago
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