Answer:
591
Step-by-step explanation:
m∠a = 56°, m∠b = 34°, m∠c = 56°
Solution:
<em>Sum of the adjacent angles in a straight line is 180°.</em>
⇒ m∠a + 124° = 180°
⇒ m∠a = 180° – 124°
⇒ m∠a = 56°
∠a and ∠c are vertically opposite angles.
Vertical angle theorem:
<em>If two lines are intersecting, then the vertically opposite angles are congruent.</em>
⇒ ∠a ≅ ∠c
⇒ m∠a = m∠c
⇒ m∠c = 56°
<em>Sum of the adjacent angles in a straight line is 180°.</em>
m∠b + 90° + m∠c = 180°
m∠b + 90° + 56° = 180°
m∠b + 146° = 180°
m∠b = 180° – 146°
m∠b = 34°
Hence m∠a = 56°, m∠b = 34°, m∠c = 56°.
Answer:
Option B. 1990 - 1992
Step-by-step explanation:
If we have to calculate inflation rate in year 2000 from 1990, we use the formula
![inflation=\frac{C.P.I. 2000-C.P.I. 1990}{C.P.I 1990}\times 100](https://tex.z-dn.net/?f=inflation%3D%5Cfrac%7BC.P.I.%202000-C.P.I.%201990%7D%7BC.P.I%201990%7D%5Ctimes%20100)
which means if consumer price index is increasing year by year the inflation rate will increase.
Now we analyse our options given with the help of graph given.
A. from 1994 - 2000
Consumer price index increased from year 1994 to 1998 but decreased between 1998 to 2000.
So this option doesn't show the continuous inflation.
B. Year 1990 - 1992
We find a continuous increase in C.P.I. therefore there will be a continuous increase in inflation.
So this option is correct.
C. Year 1992 - 1996
In this gap we see deflation from year 1992 to 1994 then inflation between 1994 - 1996.
So there is ups and downs in this period showing discontinuity in inflation.
D. 1992 - 1994
There is continuous decrease in C.P.I. so continuous deflation is reported between this period.
It's not the correct option.
Answer is Option B.
Given : In Right triangle ABC, AC=6 cm, BC=8 cm.Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5.
To find : Area (ΔMNC)
Solution: In Δ ABC, right angled at C,
AC= 6 cm, BC= 8 cm
Using pythagoras theorem
AB² =AC²+ BC²
=6²+8²
= 36 + 64
→AB² =100
→AB² =10²
→AB =10
Also, AM:MN:NB=1:2.5:1.5
Then AM, MN, NB are k, 2.5 k, 1.5 k.
→2.5 k + k+1.5 k= 10
→ 5 k =10
Dividing both sides by 2, we get
→ k =2
MN=2.5×2=5 cm, NB=1.5×2=3 cm, AM=2 cm
As Δ ACB and ΔMNC are similar by SAS.
So when triangles are similar , their sides are proportional and ratio of their areas is equal to square of their corresponding sides.
![\frac{Ar(ACB)}{Ar(MNC)}=[\frac{10}{5}]^{2}](https://tex.z-dn.net/?f=%5Cfrac%7BAr%28ACB%29%7D%7BAr%28MNC%29%7D%3D%5B%5Cfrac%7B10%7D%7B5%7D%5D%5E%7B2%7D)
![\frac{Ar(ACB)}{Ar(MNC)}=4](https://tex.z-dn.net/?f=%5Cfrac%7BAr%28ACB%29%7D%7BAr%28MNC%29%7D%3D4)
But Area (ΔACB)=1/2×6×8= 24 cm²[ACB is a right angled triangle]
![\frac{24}{Ar(MNC)}=4](https://tex.z-dn.net/?f=%5Cfrac%7B24%7D%7BAr%28MNC%29%7D%3D4)
→ Area(ΔMNC)=24÷4
→Area(ΔMNC)=6 cm²
Answer:
sorry cant help not sorry
Step-by-step explanation: