First we can find the perimeter of the given rectangle
P=2L+2W (L=length and W=width)
P=2*3+2*4
P=6+8
P=14
So now we want to come up with a different combination of numbers that would give up a perimeter of 14. We know that 14 is divisible by 2 so let's make out width 2. If we plug in 2 as the width and 14 as the perimeters, we can solve for length
14=2L+2*2
14=2L+4
10=2L (subtract 4 from both sides)
L=5
So the dimensions are 5 units and 2 units
Hope this helps!
Anything without a variable in front.
In other words, the constants are -3.7 and 1/3
I think answer is b that is 10raise to 2
