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Volgvan
3 years ago
12

Brodrick correctly represents a composite number as the product of a pair of prime factors. Which equation could show Brodricks

work? F-5×15=75 G-7×17=119 H-9×19=171 J-11×21=231
Mathematics
1 answer:
olchik [2.2K]3 years ago
4 0

Answer:

G-7×17=119

Step-by-step explanation:

A prime number is a number which has only two factors, 1 and itself.

A composite number on the other hand is any number that has more than two factors.

In the options

In F-5×15=75, 15 can still be decomposed into 5X3

In H-9×19=171, 9 can still be decomposed into 3X3

In J-11×21=231, 21 can still be written as 7X3.

So option G is the only equation which could show Brodricks work.

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Evaluate the given numerical expression <br> (5+7 to the 3rd power divided by 7 times 7
-BARSIC- [3]

{(5 + 7)}^{3}  \div 7 \times 7 \\  {12}^{3}  \div 7 \times 7 \\ 1728 \div 7 \times 7 \\ 1728

8 0
2 years ago
Which statement describes if there is an extraneous solution to the equation √x-3 = x-5? A. there are no solutions to the equati
Brrunno [24]
Remember that <span>an extraneous solution of an equation, is the solution that emerges from solving the equation but is not a valid solution.
 
Lets solve our equation to find out what is the extraneous solution:
</span>\sqrt{x-3} =x-5
(\sqrt{x-3})^2 =(x-5)^2
x-3=x^2-10x+25
x^2-11x+28=0
(x-4)(x-7)=0
x-4=0 and x-7=0
x=4 and x=7
<span>
So, the solutions of our equation are </span>x=4 and x=7. Lets replace each solution in our original equation to check if they are valid solutions:
- For x=7
\sqrt{x-3} =x-5
\sqrt{7-3} =7-5
\sqrt{4} =2
2=2
We can conclude that 7 is a valid solution of the equation.

- For x=4
\sqrt{x-3} =x-5
\sqrt{4-3} =4-5
\sqrt{1} =1
1 \neq 1
We can conclude that 4 is not a valid solution of the equation; therefore, 4 is a extraneous solution.

We can conclude that the correct answer is: <span>D. the extraneous solution is x = 4</span>
7 0
2 years ago
What is the answer to 5+5(x+4)≤20?
Nata [24]
5+5\left( x+4 \right) \le 20\\ \\ 5\left\{ 1+\left( x+4 \right)  \right\} \le 20\\ \\ \frac { 1 }{ 5 } \cdot 5\left\{ 1+\left( x+4 \right)  \right\} \le 20\cdot \frac { 1 }{ 5 }

\ \\ 1+\left( x+4 \right) \le 4\\ \\ 1+x+4\le 4\\ \\ x+5\le 4\\ \\ x\le 4-5\\ \\ x\le -1
7 0
3 years ago
Read 2 more answers
Tyler can swim 1/2 miles in 1/3 hours at a constant speed. At this rate , how fast does Tyler swin in miles for hours?
gladu [14]
Miles. Hours

1/2 = 1/3
1 = 2/3
1 1/2 = 3/3 or 1

= 1
8 0
2 years ago
8time-5=12time+1 solve the equation
zalisa [80]
1 * 12 = -40
12 = -40

Since its not possible for twelve to equal negative-forty, than there is no answer for this equation.

5 0
3 years ago
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