Sinθ = (2/3) tanθ < 0 Implies tanθ = Negative.
For sin positive and tan negative, implies θ is in the second quadrant.
<span>Sinθ = (2/3) = opposite / Hypotenuse.
Adjacent side:
x</span>² + 2² = 3²
x² + 4 = 9<span>
</span>x<span>² = 9 - 4
</span>
x<span>² = 5
</span><span>
x = </span>√5 = Adjacent.
<span>
cos</span>θ = Adjacent / Hypotenuse = √5 / 3
<span>
Since </span><span>θ is in the second quadrant, cosine is also negative in the second quadrant.
</span><span>
Therefore:
</span>cos<span>θ = - (√5/3)
</span>
The last option from the top : <span>negative square root of 5 over 3</span>
Answer:
Step-by-step explanation:
7 choose 2 or
=7! / (7-2)!
=7*6*5*4*3*2*1 / 5*4*3*2*1
=7*6
=42
Answer:
To use the vertical line test, take a ruler or other straight edge and draw a line parallel to the y-axis for any chosen value of x. If the vertical line you drew intersects the graph more than once for any value of x then the graph is not the graph of a function.
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Hope it helps you
