Answer:
74893 students per year
Step-by-step explanation:
The Average rate of change is calculated as
= Difference in number of students / Difference in years
= 3120 thousand - 5217 thousands/ 2008 - 1980
= (3120000 - 5217000)/(2008 - 1980)
= -2097000/28
= -74892.857143 per year
Therefore, the average rate of change
per year in the number of high school dropouts is approximately 74893 students per year
Answer:
166.666667 m/ps
Step-by-step explanation:
600/60 will give us the amount of kilometers in a minute. 10 km/ph, now i'll divide more to find the seconds. 0.166666667 this is the amount of KILOMETERS in a second, we are trying to find in meters. multiply by 1000 and 166.666667. a fast fricking train if you ask me.
Answer:
of what?
Step-by-step explanation:
Answer:
x = 6.39, y = 1.69 is the solution of the given equation system.
Step-by-step explanation:
Here, the given set of equation is:
5 x = 15 + 10 y ⇒ 5 x - 10 y = 15 ...... (1)
3 x +7 y = 31 ............. (2)
Now, the coefficient of x in first equation id 5 and in second is 3.
So, MULTIPLY (1) with 3 and (2) with -5 , we get:
15 x - 30 y = 45
-15 x- 35 y = -155
<u>ADD BOTH EQUATIONS ,</u> we get:
15 x - 30 y -15 x- 35 y = 45 - 155
or, -65 y = -110
or, y = 110/65 = 1.69
Put y = 1.69 in 3 x +7 y = 31 , we get:
3(x) + 7 (1.69) =31
⇒ 3 x = 19.17 or x = 6.39
Hence, x = 6.39, y = 1.69 is the solution of the given equation system
To set up or model a linear equation to fit a real-world application, we must first determine the known quantities and define the unknown quantity as a variable. Then, we begin to interpret the words as mathematical expressions using mathematical symbols. Let us use the car rental example above. In this case, a known cost, such as $0.10/mi, is multiplied by an unknown quantity, the number of miles driven. Therefore, we can write
0.10
x
. This expression represents a variable cost because it changes according to the number of miles driven.
If a quantity is independent of a variable, we usually just add or subtract it according to the problem. As these amounts do not change, we call them fixed costs. Consider a car rental agency that charges $0.10/mi plus a daily fee of $50. We can use these quantities to model an equation that can be used to find the daily car rental cost
C
.
C
=
0.10
x
+
50
When dealing with real-world applications, there are certain expressions that we can translate directly into math. The table lists some common verbal expressions and their equivalent mathematical expressions.
