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cestrela7 [59]
3 years ago
11

-8x-3(1+2x) distributions

Mathematics
1 answer:
Valentin [98]3 years ago
8 0
<span>-8x-3(1+2x)
= </span><span>-8x -3 - 6x
= -14x - 3</span>
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How would you use the Fundamental Theorem of Calculus to determine the value(s) of b if the area under the graph g(x)=4x between
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The Fundamental Theorem of Calculus regarding geometry states that 
\int\limits^b_a g{(x)} \, dx = F(b)-F(a)

Where F is the indefinite integral of g(x)

The first step is to integrate g(x)
\int\ {4x} \, dx = \frac{4x^{1+1} }{1+1} = \frac{4x^{2} }{2} =2 x^{2}

Then substitute the value of b and a=1 into 2x^{2}

[2 (b)^{2}]-[2 (1)^{2}] = 240
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b^{2}=121
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Hence the limit of the area under g(x) is between a=1 and b=11

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3 years ago
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