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3 years ago

I need to check a number line of 0 to 4 using 1/3

1 answer:

7 0

Draw a straight line. Label the left side "0" and then make lines with
"2" "3" and "4".

1/3 means it i 1/3rd of 1. Which means you need to divide everything from 0 - 1 into 2 segments. The first segment on the left side is your 1/3rd spot. The next one is your 2/3rd place, and then finally the 1 is your 3/3 (or one whole.)

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Two angles are said to be congruent if

dem82 [27]

Congruent means Same Side, Same Shape.
If two angles are congruent, they are to be of the same size and same shape or a fraction of it (Dilation)

6 0

3 years ago

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HELLOOOO HELP PLEASE

MA_775_DIABLO [31]

Answer:

$2*log(x)+log(y)$

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

<em>Logarithm of a power</em>:

$log_ba^c=c*log_ba$

So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: $log_ba=x\implies b^x=a$

Now if we raise both sides to the power of c, we get the following equation: $(b^x)^c=a^c$

Using the exponential identity: $(x^a)^c=x^{a*c}$

We get the equation: $b^{xc}=a^c$

If we convert this back into logarithmic form we get: $log_ba^c=x*c$

Since x was the basic logarithm we started with, we substitute it back in, to get the equation: $log_ba^c=c*log_ba$

Now the second logarithmic property you need to know is

<em>The Logarithm of a Product</em>:

$log_b{ac}=log_ba+log_bc$

Now for a quick proof, let's just say: $x=log_ba\text{ and }y=log_bc$

Now rewriting them both in exponential form, we get the equations:

$b^x=a\\b^y=c$

We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

$b^x*b^y=a*c$

Using the exponential identity: $x^{a}*x^b=x^{a+b}$ , we can rewrite the equation as:

$b^{x+y}=ac$

taking the logarithm of both sides, we get:

$log_bac=x+y$

Since x and y are just the logarithms we started with, we can substitute them back in to get: $log_bac=log_ba+log_bc$

Now let's use these identities to rewrite the equation you gave

$log(x^2y)$

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

$log(x^2)+log(y)$

Now using the logarithm of a power to rewrite the log(x^2) we get:

$2*log(x)+log(y)$

3 0

1 year ago

What is a equation for line with a slope o 2/3 and a y-intercept of (0,0)

Lerok [7]

Answer:

y= 2/3 x

Step-by-step explanation:

point slope form

y-y1 = m(x-x1)

y-0 = 2/3 (x-0)

y = 2/3(x)

y= 2/3 x

3 0

2 years ago

What is 36÷2/3×9×1/2

krok68 [10]

Answer:

1/3

Step-by-step explanation:

Simplify the following:

((36/2)/(3×9))/2

((36/2)/(3×9))/2 = 36/(3×9×2×2):

36/(3×9×2×2)

36/9 = (9×4)/9 = 4:

4/(3×2×2)

4/2 = (2×2)/2 = 2:

2/(3×2)

2/(3×2) = 2/2×1/3 = 1/3:

Answer: 1/3

6 0

3 years ago

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An angle is bisected, forming two new angles. If the original angle had a measure of 56°, what is the measure of each new angle?

IrinaVladis [17]

Answer:

Step-by-step explanation:

4 0

3 years ago

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