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MAVERICK [17]
3 years ago
8

In 1990, a person is 15 years old.

Mathematics
2 answers:
Sergio039 [100]3 years ago
7 0

Answer:

it isn't in the AD it is in BC

Step-by-step explanation: In BC the years count backwards compared to today

Evgesh-ka [11]3 years ago
6 0

Answer:

Well, if this were to be BC= Before Christ, the years would go back.

Step-by-step explanation:

And that's why the question is trying to trick you. So in 1990 BC the person is 15 years old. 5 years later, the same person is now 10 years. 5 years back is the order of the BC concept. Hope this makes sense!

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Harry buys 22 fish he has a round fish bowl and a rectangular fish tank how could he place the fish in the bowl and tank. Equati
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Answer:

11 and 11 in each of each fish tank or put more fish in the rectangular fish tank


5 0
3 years ago
Evaluate the following expression for w=4. w^-3 =
slega [8]
W^-3
(4)^-3 = 1/(4)^3
1/64.

The solution is 1/64.
6 0
3 years ago
The image shows parallel lines cut by a transversal. The expressions represent unknown angle measurements. What is the value of
Triss [41]
Answer) C. 77
This picture shows how I got to the answer. You must set up the two expressions to equal each other and then solve for X

7 0
4 years ago
Can you answer these please many thanks
givi [52]

Given: (a) 2(x+3)=2x+6 and (b) 4(y-3)=4y-12.

To find: The expanded form of the given expressions.

(c) 4(m+n)=4m+4n       (using a(b+c)=ab+ac)

(d) 3(5-q)=15-3q           (using a(b-c)=ab-ac)

(e) 5(2c+1)=10c+5          (using a(b+c)=ab+ac)

(f) 3(2x-5)=6x-15          (using a(b-c)=ab-ac)

(g) 7(4b-1)=28b-7          (using a(b-c)=ab-ac)

(h) 3(2x+y-5)=3((2x+y)-5)

⇒3(2x+y-5)=3(2x+y)-15         (using a(b-c)=ab-ac)

⇒3(2x+y-5)=6x+3y-15            (using a(b+c)=ab+ac)

(i) 2(6a-4b+3)=2((6a-4b)+3)

⇒2(6a-4b+3)=2(6a-4b)+6         (using a(b+c)=ab+ac)

⇒2(6a-4b+3)=12a-8b+6            (using a(b-c)=ab-ac)

(j)6(m+n+p)=6((m+n)+p)

⇒ 6(m+n+p)=6(m+n)+6p           (using a(b+c)=ab+ac)

⇒ 6(m+n+p)=6m+6n+6p            (using a(b+c)=ab+ac)

(k) y(y+2)=y^2+2y          (using a(b+c)=ab+ac)

(l) g(g-3)=g^2-3g           (using a(b-c)=ab-ac)

(m) n(4-n)=4n-n^2        (using a(b-c)=ab-ac)

(n) a(b+c)=ab+ac           (using a(b+c)=ab+ac)

(o) s(3s-4)=3s^2-4s        (using a(b-c)=ab-ac)

(p) 2x(x+5)=2x^2+10x     (using a(b+c)=ab+ac)

(q) 4y(x-3)=4xy-12y      (using a(b-c)=ab-ac)

(r) 5a(2b-5)=10ab-25a     (using a(b-c)=ab-ac)

(s) 4a(3b+2c)=12ab+8ac    (using a(b+c)=ab+ac)

(t) 5p(4p-5q)=20p^2-25pq    (using a(b-c)=ab-ac)

6 0
3 years ago
Can someone help with this geometry question?
Alex787 [66]

since it's rhombus, then

6x-11=25-4x

10x=36

x=3.6

each side = 25-4(3.6)

= 25 - 14.4

= 10.6

3 0
3 years ago
Read 2 more answers
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