option is incorrect the last option should be reverse
Let us say,
Price of adult ticket=x
Price of child ticket =y
On the first day ticket sales the school sold 4 adult tickets and 12 child tickets for total of $80
4x+12y=80.............(1)
took $41 on the second day by selling 1 adult ticket and 10 child tickets
1x+10y=41.............(2)
x=41-10y..............(3)
plugging the value of x from equation (3) in equation (1) we get,
4(41-10y)+12y=80
164-40y+12y=80
84=28y
y=3
plugging this value of y in equation (2) we get,
1x+10(3)=41
x=11
Price of adult ticket= 11 dollars
Price of child ticket = 3 dollars
1 Simplify \frac{14}{30}
30
14
to \frac{7}{15}
15
7
.
\frac{7}{15}\div 14.00
15
7
÷14.00
2 Use this rule: a\div \frac{b}{c}=a\times \frac{c}{b}a÷
c
b
=a×
b
c
.
\frac{7}{15}\times \frac{1}{14.00}
15
7
×
14.00
1
3 Use this rule: \frac{a}{b}\times \frac{c}{d}=\frac{ac}{bd}
b
a
×
d
c
=
bd
ac
.
\frac{7\times 1}{15\times 14.00}
15×14.00
7×1
4 Simplify 7\times 17×1 to 77.
\frac{7}{15\times 14.00}
15×14.00
7
5 Simplify 15\times 14.0015×14.00 to 210210.
\frac{7}{210}
210
7
6 Simplify.
1/30
Answer:
B
Step-by-step explanation:
sinA=opp/hyp
sinA=16/20=4/5
cosA=adj/hyp
cosA=12/20=3/5
