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4 years ago

Which classification describes the system of linear equations?

Mathematics

1 answer:

katen-ka-za [31]4 years ago

5 0

Both equations are the same
y=−4x+4 ----> y+4x=4,
so consistent dependent

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Complete the following invoice for upholstery fabric.

Degger [83]

Answer:

a) $49.48

b) $220921.91

Step-by-step explanation:

(a) 4 yd @ $12.37 per yd = 4 x $12.37 = $49.48

(b) 271 yd @ 815.21 per yd = 271 x $815.21 = $220921.91

(c) 20% yd @ $4.95 per yd : Here the nunber of yards are missing. Hence could not be answer . However if number of yards is x . The answer would be

20% of 4.95x

(20%=0.20)

0.20 × 4.95x

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3 years ago

A.perform the indicated operation. 1.(6x-4)+(-2x+2) Solution and answer:

Anestetic [448]

Answer:

4x - 2

Step-by-step explanation:

(2(3x-2))+(-2(x-1))

2(3x-2)-2(x-1)

2(3x-2-(x-1))

2(3x-2-x+1)

2(2x-1)

4x-2

3 0

4 years ago

PLEASE HELP!!! WILL GIVE BRAINLIEST!!!

777dan777 [17]

Answer: (2,2) and (-5,16)

Step-by-step explanation:

Here we have both Line (Linear Function) and Parabola (Quadratic Function)

So I am gonna write these equations here,

$y=x^2+x-4\\y=-2x+6$

The first equation has Parabola graph (Since it's second degree.)

and the second equation has line graph.

To find the intersection, you have to substitute either -2x+6 in first equation (Quadratic) or x^2+x-4 in second equation (Linear)

For me, I am going to substitute x^2+x-4 in y=-2x+6.

$x^2+x-4=-2x+6$

Now solve the equation and find the value of x.

Since it's Quadratic Equation (Because there's x^2) I'd move -2x+6 to the left side.

$x^2+x-4+2x-6=0$ Finish things here (Subtract and Addition)

$x^2+3x-10=0$ What two numbers multiply to 10? Find the factors of 10, that are [1 and 10] and [2 and 5]

Now think about it, do you think that if 1 and 10 subtract or even addition, do you think that it'd be 3? No, of course not.

So 2 and 5 is right.

$(x-2)(x+5)=0$ (5-2 = 3) and (5*(-2) = -10)

Then we get both x, $x=2,-5$

However, this is not it. You have to substitute both x in Linear Equation.

Substitute x = 2 in y=-2x+6

$y=-2(2)+6\\y=-4+6\\y=2$

Order = $(2,2)$

Then substitute x = -5 in y=-2x+6

$y=-2(-5)+6\\y=10+6\\y=16$

Order = $(-5,16)$

So the intersections are both (2,2) and (-5,16) as shown in graph below.

4 0

4 years ago

Zander was given two functions: the one represented by the graph and the function f(x) = (x + 4)2. What can he conclude about th

Svetradugi [14.3K]

The conclusion about the functions is they have the same y-intercept.

<h3>How to make conclusion about the functions?</h3>

The complete question is added as an attachment

The function is given as:

f(x) = (x + 4)^2

From the attached graph, the graph has a y-intercept at:

y = 16

This can be represented as:

(0, 16)

Next, we set x = 0 in f(x) = (x + 4)^2

f(0) = (0 + 4)^2

Evaluate

f(0) = 16

This means that the y-intercept of f(x) = (x + 4)^2 is (0, 16)

So, the functions have the same y-intercept

Hence, the conclusion about the functions is they have the same y-intercept.