Stuart decides there are no odd square numbers. His justification is that ‘because an even number multiplied by an even number p
roduces an even number, and that an odd number multiplied by an odd number also produces an even number, then there are no odd square numbers’. Do you agree with Stuart’s claim? If not, give an example to explain your answer. Please explain
This is false because 3 times 3=9 and all of those are odd odd nubmers are represented by 2n+1 where n= a natural number (whhole numbers and negatives) so (2n+1) squared=(2n+1)(2n+1)=4n^2+4n+1 (a whole number times an even number yeilds an even number because an
even number is represented by 2n where n=a natrual number so 2n times
x=2nx which is still even.) since n represents a whole number and a whole number times an even number (4) equals an even number, 4n^2 and 4n must be even, and even+even=even that leavs the +1 at the end we know that even+1=odd so therefor any odd number squared results in an odd nnumber
