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devlian [24]
3 years ago
9

If g(x)=1-3/4x find the values of g(0), and -5·g(4)-1

Mathematics
1 answer:
mezya [45]3 years ago
5 0

Answer:

What is the math qouestion, what are we trying to find out?

Step-by-step explanation:

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A DVD sales rack has 23 comedies, 13 dramas, 10 science fiction movies, and 31 action movies. How many DVDs are on the sales rac
adelina 88 [10]
I think there are 77 if i can add correctly XD
4 0
3 years ago
Read 2 more answers
(5 points) An urn contains two blue balls denoted by B1 and B2, and three white balls denoted by W1, W2 and W3. One ball is draw
never [62]

Answer:

The probability of the event that first ball that is drawn is blue  is \frac 25.

Step-by-step explanation:

Probability:

If S is is an sample space in which all outcomes are equally likely and E is an event in S, then the probability of E,denoted P(E) is

P(E)=\frac{\textrm{The number of outcomes E}}{\textrm{The total number outcomes of S}}

Given that,

An urn contains two balls B₁ and  B₂ which are blue in color and W₁,W₂ and W₃ which are white in color.

Total number of ball =(2+3) =5

The number ways of selection 2 ball out of 5 ball is

=5²

=25

Total outcomes = 25

List of all outcomes in the event that the first ball that is drawn is blue are

B₁B₁ , B₁B₂ , B₁W₁ , B₁W₂ , B₁W₃ , B₂B₁ , B₂B₂ ,  B₂W₁ , B₂W₂ , B₂W₃

The number of event that the first ball that is drawn is blue is

=10.

The probability of the event that first ball that is drawn is blue  is

=\frac{10}{25}

=\frac25

3 0
3 years ago
A marketing research firm wishes to compare the prices charged by two supermarket chains—Miller’s and Albert’s. The research fir
AVprozaik [17]

Answer:

a) F=\frac{s^2_2}{s^2_1}=\frac{1.84^2}{1.4^2}=1.727 \approx 1.73

b) For this case since we have a two tailed test we have two critical values, and we can find the two values since we need that on each tail the area would be \alpha/2 =0.025, the distribution is the F with 9 df for the numerator and denominator, and we can use the following excel codes to find the critical values:

"=F.INV(0.025,9,9)"

"=F.INV(1-0.025,9,9)"

The two critical values are 0.248 and 4.026, so the rejection zone would be: F>4.026 \cup F since our calculated value is not on the rejection zone we fail to rejec the null hypothesis

Step-by-step explanation:

Data given and notation  

n_1 = 10 represent the sampe size for the Miller's Stores

n_2 =10 represent the sample size for the Albert's stores

\bar X_1 =121.92 represent the sample mean for Miller's store

\bar X_2 =114.81 represent the sample mean for Albert's store

s_1 = 1.4 represent the sample deviation for the Miller's store

s_2 = 1.84 represent the sample deviation for the Albert's stores

s^2_2 = 12.25 represent the sample variance for the utility stocks

\alpha=0.05 represent the significance level provided

Confidence =0.95 or 95%

F test is a statistical test that uses a F Statistic to compare two population variances, with the sample deviations s1 and s2. The F statistic is always positive number since the variance it's always higher than 0. The statistic is given by:

F=\frac{s^2_2}{s^2_1}

Solution to the problem  

System of hypothesis

We want to test if the variation for th two groups is the same, so the system of hypothesis are:

H0: \sigma^2_1 = \sigma^2_2

H1: \sigma^2_1 \new \sigma^2_2

a) Calculate the statistic

Now we can calculate the statistic like this:

F=\frac{s^2_2}{s^2_1}=\frac{1.84^2}{1.4^2}=1.727 \approx 1.73

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have n_1 -1 =10-1=9 and for the denominator we have n_2 -1 =10-1=9 and the F statistic have 9 degrees of freedom for the numerator and 9 for the denominator. And the P value is given by:

P value

p_v =2*P(F_{9,9}>1.727)=0.428

And we can use the following excel code to find the p value:"=2*(1-F.DIST(1.727,9,9,TRUE))"

b) Critical value

For this case since we have a two tailed test we have two critical values, and we can find the two values since we need that on each tail the area would be \alpha/2 =0.025, the distribution is the F with 9 df for the numerator and denominator, and we can use the following excel codes to find the critical values:

"=F.INV(0.025,9,9)"

"=F.INV(1-0.025,9,9)"

The two critical values are 0.248 and 4.026, so the rejection zone would be: F>4.026 \cup F since our calculated value is not on the rejection zone we fail to rejec the null hypothesis

Since our calcu

Conclusion

Since the p_v > \alpha we have enough evidence to FAIL to reject the null hypothesis. And we can say that we don't have enough evidence to conclude that the two deviations are different at 5% of significance.  

8 0
3 years ago
Given that T is squidistant from U and S find x
Temka [501]
Found the figure:TU = 7TS = x - 1Since T is equidistant from u and s, this means that TU = TS7 = x - 17 + 1 = x8 = xThe  ...
3 0
3 years ago
561
kiruha [24]

Answer:

12

563 - (563x0.25) = 422.25 -> 422

16

422 -(422x0.25) = 316.5 -> 317

20

317 - (317x0.25) = 237.75 -> 238

24

238 - (238x0.25) = 178.5 -> 179

28 (continue the step by step process)

134.25 -> 134

32

100.5 -> 101

36

75.75 -> 76

40

57

44

42.75 -> 43

48

32.25 -> 32

52

24

56

18

Step-by-step explanation:

the time interval has to keep skipping by four hours because the medicine is filtered in that amount of time.

The multiplying by 0.25 part must be done first in order to show how much the kidney has filtered.

after this, you need to subtract that from how many milligrams of medicine are left in your system

note that if you do not subtract, you will only be showing how much the kidney has filtered. the question asks for how much is left in the SYSTEM overall, so subtracting is quite necessary to completely answer the question.

I hope this helped.

7 0
3 years ago
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