The probability that Rebecka selects a terrier and Aaron selects a retriever is 10/121
<h3>How to determine the probability?</h3>
The distribution of the puppies is given as:
4 poodles, 5 terriers, and 2 retrievers
The probability of selecting a terrier is;
P(terrier) = 5/11
The probability of selecting a retriever is;
P(retriever) = 2/11
The required probability is
P = 5/11 * 2/11
Evaluate
P = 10/121
Hence, the probability that Rebecka selects a terrier and Aaron selects a retriever is 10/121
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The answer is C
Hope it helped
1. find equation
general solutions are:
for P(0,-11)
⇒
for p(1,-13)
and
solve for a and b:
the total equation is now:
To find the x-intercept set y=0 and solve for x
An angle bisector is a line or ray that divides an angle into two congruent angles
so
in this problem
m∠RST=m∠RSV+m∠VST
m∠RSV=m∠VST
hence
m∠RST=2*m∠RSV --------> equation 1
we have
m∠RST=(6x-24)
m∠RSV=(2x+8)
Substitute in the equation 1
6x-24=2*(2x+8)
6x-24=4x+16
6x-4x=16+24
2x=40
x=40/2
x=20 degrees
therefore
the value of x is 20 degrees
Tell me if I’m wrong
