Could you possibly post a more high quality picture so its not blurry thanks!
Imaginary number is one that when squared gives a negative result. ... With imaginary numbers, when you square them, the answer is negative. They are written like a real number, but with the letter i after them, like this: 23iThe letter i means it is an imaginary number.
Let the number of pepperoni pizzas be x
pepperoni = x
veggie = x - 8 [<span>There were eight fewer veggie than pepperoni]
</span>combo = 3x [T<span>here were three times as many combo as pepperoni]
</span>
Given that the total Pizza: 112
x + x - 8 + 3x = 112
5x - 8 = 112
5x = 112 + 8
5x = 120
x = 24
x= 24
x - 8 = 16
3x = 72
So there were 24 pepperoni pizza, 16 veggie pizza and 72 combo pizza
8x - 2y = 48, y =4
8x - 2(4) = 48
8x - 8 = 48
8x = 48+8
8x = 56
x = 56/8 = 7
x = 7
Answer:
both kinds of tickets are $5 each
Step-by-step explanation:
Let s and c represent the dollar costs of a senior ticket and child ticket, respectively. The problem statement describes two relationships:
12s + 5c = 85 . . . . . revenue from the first day of sales
6s + 9c = 75 . . . . . . revenue from the second day of sales
Double the second equation and subtract the first to eliminate the s variable.
2(6s +9c) -(12s +5c) = 2(75) -(85)
13c = 65 . . . . . simplify
65/13 = c = 5 . . . . . divide by the coefficient of c
Substitute this value into either equation. Let's use the second one.
6s + 9·5 = 75
6s = 30 . . . . . . . subtract 45
30/6 = s = 5 . . . divide by the coefficient of s
The price of a senior ticket is $5; the price of a child ticket is $5.
