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ludmilkaskok [199]
2 years ago
15

In the triangle below,

Mathematics
1 answer:
defon2 years ago
3 0

Answer: y ≈ 10.6 cm

Step-by-step explanation:

The cosine function relates the adjacent side to the hypotenuse in a right triangle. The side adjacent to the 20° angle is 10 cm.

cos(20°) = (10 cm)/y

y = (10 cm)/cos(20°)

y ≈ 10.6 cm

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Bond [772]
(-7) * 8 = -56

answer
A. -56

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3 years ago
Kevin is an employee at Good Deal Electronics. The electricity is not working one day after a thunderstorm, but Kevin still has
dimulka [17.4K]

Answer:

56

Step-by-step explanation:

7 0
2 years ago
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If f(x) = -3x + 4, find f(3x + 3)
Alex17521 [72]

Remark

What this is telling you to do is put 3x + 3 in the question wherever there was an x to start with.

Solution

f(x) = -3x + 4

f(3x + 3) = - 3(3x + 3) + 4

f(3x + 3) = -3*3x + (-3)*(3) + 4

f(3x + 3) = - 9x - 9 + 4

f(3x + 3) = -9x - 5 <<<<< Answer

8 0
3 years ago
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What is the value of s and the length of side BC if ABCD is a rhombus?
Natali5045456 [20]

Step 1

<u>Find the value of s</u>

we know that

In a Rhombus all sides are congruent

so

AB=BC=CD=DA

AB=9s+29\\CD=10s-16

equate AB and CD

9s+29=10s-16\\

Combine like term

10s-9s=29+16\\

s=45\ units

<u>The answer Part a) is</u>

the value of s is 45\ units

Step 2

<u>Find the value of side AB</u>

AB=9s+29

substitute the value of s

AB=9*45+29=434\ units

Remember that the sides are congruent

AB=BC=CD=DA

therefore

<u>the answer Part b) is</u>

The length of the side BC is 434\ units


4 0
3 years ago
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The polar coordinates of a point are 3π 4 and 7.00 m. What are its Cartesian coordinates (in m)? (x, y) = 6.06,−3.5 m
Keith_Richards [23]

Answer:

a) \left(x,y\right)=\left(4.95,-4.95\right)

b) r\angle\theta = 7\angle0.5236\,\text{radians}

Step-by-step explanation:

Polar coordinates are represented as: r\angle\theta, where 'r' is the length (or magnitude) of the line, and '\theta' is the angle measured from the positive x-axis.

in our case:

7\angle\dfrac{3\pi}{4}

to covert the polar to cartesian:

x = r\cos{\theta}

y = r\sin{\theta}

we can plug in our values:

x = 7\cos{\dfrac{3\pi}{4}} = -7\dfrac{\sqrt{2}}{2}

y = 7\sin{\dfrac{3\pi}{4}} = 7\dfrac{\sqrt{2}}{2}

the Cartesian coordinates are:

\left(x,y\right)=\left(-7\dfrac{\sqrt{2}}{2},7\dfrac{\sqrt{2}}{2}\right)

\left(x,y\right)=\left(4.95,-4.95\right)

(b) to convert (x,y) = (6.06,-3.5)

we'll use the pythagoras theorem to find 'r'

r^2 = x^2+y^2

r^2 = (6.06)^2+(-3.5)^2

r = \sqrt{48.97} \approx 7

the angle can be found by:

\tan{\theta} = \dfrac{y}{x}

\tan{\theta} = \dfrac{3.5}{6.06}

\theta = \arctan{left(\dfrac{3.5}{6.06}\right)}

\theta = 0.5236 \text{radians}

to convert radians to degrees:

\theta = 0.5236 \times \dfrac{180}{\pi} \approx 30^\circ

writing in polar coordinates:

r\angle\theta = 7\angle30^\circ\,\,\text{OR}\,\,7\angle0.5236\,\text{radians}

5 0
3 years ago
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