<h3>
Answer: a = -1 (fourth choice)</h3>
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Work Shown:
q = (-4, 1) is one vector
r = (a,3) is another vector
The resultant vector is
q+r = (-4,1)+(a,3)
q+r = (-4+a,1+3)
q+r = (-4+a,4)
Multiply both sides by 7
7(q+r) = 7*(-4+a,4)
7(q+r) = (7*(-4+a),7*4)
7(q+r) = (-28+7a, 28)
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Since 7(q+r) = (-35, 28), we know that,
(-28+7a, 28) = (-35, 28)
which leads to
-28 + 7a = -35
when we equate the x components of each vector. Let's solve for 'a'
-28 + 7a = -35
7a = -35+28
7a = -7
a = -7/7
a = -1
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Check:
q = (-4,1)
r = (a,3) = (-1,3)
q+r = (-4,1)+(-1,3)
q+r = (-4+(-1), 1+3)
q+r = (-5, 4)
7*(q+r) = 7*(-5, 4)
7*(q+r) = (7*(-5), 7*4)
7*(q+r) = (-35, 28)
The answer is confirmed.
Answer:
x is a variable, it can be ANY NUMBER
Step-by-step explanation:
Answer:
The only answer I have for this could be 392in²
Answer:

Step-by-step explanation:
The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

And 0 for other case. Let X the random variable that represent "The number of years a radio functions" and we know that the distribution is given by:

We can assume that the random variable t represent the number of years that the radio is already here. So the interest is find this probability:

We have an important property on the exponential distribution called "Memoryless" property and says this:

Where a represent a shift and t the time of interest.
On this case then 
We can use the definition of the density function and find this probability:


![=[lim_{x\to\infty} (-e^{-\frac{1}{8}x})+e^{-1}]=0+e^{-1}=e^{-1}](https://tex.z-dn.net/?f=%3D%5Blim_%7Bx%5Cto%5Cinfty%7D%20%28-e%5E%7B-%5Cfrac%7B1%7D%7B8%7Dx%7D%29%2Be%5E%7B-1%7D%5D%3D0%2Be%5E%7B-1%7D%3De%5E%7B-1%7D)