Complete question :
Suppose someone gives you 8 to 2 odds that you cannot roll two even numbers with the roll of two fair dice. This means you win $8 if you succeed and you lose $2 if you fail. What is the expected value of this game to you? What can you expect if you play 100 times.
Answer:
$0.5 ; win $50 with 100 rolls
Step-by-step explanation:
From a roll of two fair dice; probability of obtaining an even number :
Even numbers = (2, 4, 6) = 3
P = 3 /6 = 1 /2
For 2 fair dice ; probability of rolling two even numbers : independent event.
1/2 * 1/2 = 1/4
Hence, p(success) = 1/4 ; P(failure) = 1 - 1/4 = 3/4
Probability table
Winning = $8 or loss = - $2
X : ____ 8 ______ - 2
P(x) __ 1/4 ______ 3/4
Expected value : E(x) = ΣX*P(x)
E(x) = (8 * 1/4) + (-2 * 3/4)
E(x) = 2 - 1.5
E(x) = $0.5
Since expected value is positive, the expect to win
If played 100 times;
Expected value = 100 * $0.5 = $50
9,864,320
Hope this helps, let me know if there's anything else I can help you with :)
Answer:
13/20
Step-by-step explanation:
5 People can be chosen in 1287 ways if the order in which they are chosen is not important.
Step-by-step explanation:
Given:
Total number of students= 13
Number of Students to be selected= 5
To Find :
The number of ways in which the 5 people can be selected=?
Solution:
Let us use the permutation and combination to solve this problem

So here , n =13 and r=5 ,
So after putting the value of n and r , the equation will be




