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kirill115 [55]
2 years ago
14

what is the quotient (65y3 15y2 − 25y) ÷ 5y? a. 13y2 3y − 5 b. 13y3 3y2 − 5y c. 13y2 − 3y 5 d.13y2 − 3y − 5

Mathematics
2 answers:
Aneli [31]2 years ago
4 0

Keywords:

<em>Division, quotient, polynomial, monomial </em>

For this case we must solve a division between a polynomial and a monomial and indicate which is the quotient.

By definition, if we have a division of the form: \frac {a} {b} = c, the quotient is given by "c".

We have the following polynomial:

65y ^ 3 + 15y ^ 2 - 25y that must be divided between monomy5y, then:

C (y) represents the quotient of the division:

C (y) = \frac {65y ^ 3 + 15y ^ 2 - 25y} {5y}

C (y) = \frac {65y ^ 3} {5y} + \frac {15y ^ 2} {5y} - \frac {25y} {5y}

C (y) = 13y ^ 2 + 3y-5

Thus, the quotient of the division between the polynomial and the monomial is given by:

C (y) = 13y ^ 2 + 3y-5

Answer:

The quotient is: C (y) = 13y ^ 2 + 3y-5

Option: A


jeka57 [31]2 years ago
3 0
When you divide each term by 5y, you are left with A's equation. The answer is A.
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0.494 is the probability that on a selected day the stock price is between $186.26 and $192.47.

Step-by-step explanation:

We are given the following information in the question:

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Standard Deviation, σ = $4.6412

We are given that the distribution of stock price is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(stock price is between $186.26 and $192.47)

P(186.26 \leq x \leq 192.47) = P(\displaystyle\frac{186.26 - 188.876}{4.6412} \leq z \leq \displaystyle\frac{192.47-188.876}{4.6412}) = P(-0.5636 \leq z \leq 0.7743)\\\\= P(z \leq 0.7743) - P(z < -0.5636)\\= 0.781 - 0.287 = 0.494 = 49.4\%

P(186.26 \leq x \leq 192.47) = 49.4\%

0.494 is the probability that on a selected day the stock price is between $186.26 and $192.47.

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