Let n be the larger integer and n-2 be the smaller integer.
n² - (n - 2)²
= n² - (n - 2)(n - 2)
= n² - (n² - 4n - 4)
= n² - n² + 4n + 4
= 4n + 4
= 4(n + 1)
No matter what value n is, it will always be a multiple of 4.
Answer:
2.83
Step-by-step explanation:
25 round off is equal to 30
so we can write 2.825 = 2.83 in form of 2 digits
83 round off to 80
2.83 is equal to 2.8
Answer:
- 40, - 50, - 60
Step-by-step explanation:
Note the common difference d between consecutive terms of the sequence.
- 20 - (- 10) = - 20 + 10 = - 10
- 30 - (- 20) = - 30 + 20 = - 10
Thus the difference d = - 10
To obtain a term in the sequence subtract 10 from the previous term
- 30 - 10 = - 40
- 40 - 10 = - 50
- 50 - 10 = - 60
The next 3 terms are - 40, - 50, - 60
Answer: 3/4 is the answer