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Gelneren [198K]
3 years ago
6

If a + b = 6 and a - b = 4, What is the value of 2a + 3b?

Mathematics
2 answers:
tangare [24]3 years ago
4 0
The value of 2a + 3b is 13
Luden [163]3 years ago
3 0

Answer:

13

Step-by-step explanation:

a + b = 6 and a - b = 4

Add the two equations together

a + b = 6

a - b = 4

----------------

2a = 10

Subtract the two equations

a + b = 6

- a + b = -4

----------------

2b = 2

b =1

Multiply by 3

3b =3

2a +3b

we know 2a = 10 and 3b = 3

10+3

13

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I need help with my math!!!!!!!
olga_2 [115]

Answer:

2\sqrt{6}

Step-by-step explanation:

Area of a square = s^{2}   (<em>s is a side length)</em>

<em>24 = </em>s^{2}

\sqrt{24} = \sqrt{s^{2} }

\sqrt{24} = <em>s</em>

\sqrt{(4)(6) } = <em>s</em>

<em>2</em>\sqrt{6} = <em>s</em>

7 0
3 years ago
What is the midpoint of the line segment with endpoints of (-2,-2) and (4,6)?
slamgirl [31]

Answer:

option (d) is correct.

The mid points of the line segment whose ends points are (-2,-2) and (4,6) is (1,2)

Step-by-step explanation:

Given: end points of a line segment as (-2,-2) and (4,6)

We have to find the mid points of the line segment whose ends points are given.

Mid point formula is stated as ,

For a line having end points as \left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right) , the mid point can be calculated as,

\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

Here,

\left(x_1,\:y_1\right)=\left(-2,\:-2\right),\:\left(x_2,\:y_2\right)=\left(4,\:6\right)

Substitute in mid point formula, we get,

=\left(\frac{4-2}{2},\:\frac{6-2}{2}\right)

Solving further , we get,

=\left(1,\:2\right)

Thus, the mid points of the line segment whose ends points are (-2,-2) and (4,6) is (1,2)

Thus, option (d) is correct.

6 0
3 years ago
Read 2 more answers
Gianna is going to throw a ball from the top floor of her middle school. When she throws the hall from 48 feet above the ground,
vazorg [7]

Answer:

So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.

Step-by-step explanation:

The height h of the ball is modeled by the following equation

h(t)=-16t^2+32t+48

The problem want you to find the times the ball will be 48 feet above the ground.

It is going to be when:

h(t) = 48

h(t)=-16t^{2}+32t+48

48=-16t^{2}+32t+48

0=-16t^{2}+32t+48 - 48

16t^{2} - 32t = 0

We can simplify by 16t. So

16t(t-2)= 0

It means that

16t = 0

t = 0

or

t - 2 = 0

t = 2

So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.

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3 years ago
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sleet_krkn [62]
108/9=12 is a true statement
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3 years ago
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Answer:

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Step-by-step explanation:

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