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MatroZZZ [7]
3 years ago
13

The number of milligrams Dh of a drug in a patient's bloodstream h hours after the drug is injected is modeled by the following

function. =Dh35e−0.15h Find the initial amount injected and the amount in the bloodstream after 8 hours. Round your answers to the nearest hundredth as necessary.
Mathematics
1 answer:
hodyreva [135]3 years ago
4 0

We assume you intend

D(h)=35e^{-0.15h}

You want to evaluate this function for h=0 and h=8.

D(0)=35e^{0}=35\\D(8)=35e^{-0.15\cdot 8}\approx 10.54

The amount injected was 35 milligrams; 8 hours later 10.54 milligrams remained.

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Possible values are 

x=1,y=11

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Mr yates owns a smoothie shop. To mix a batch of his famous orange punch smoothies, he uses 18 ounces of freshly squeezed orange
HACTEHA [7]

Answer:

31 batches

Step-by-step explanation:

Find how many batches of orange punch smoothies he can make by dividing 560 by 18:

560/18

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Since we can only have a whole number answer, round down.

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4 0
3 years ago
What's the product of 12.34•0•74.91 ?
Eduardwww [97]
Because there is a zero in the expression 12.34 * 0 * 74.91 the product is 0.
4 0
3 years ago
Read 2 more answers
Factor 8x^3y + 38x^2y - 10xy
Sophie [7]

Answer:

2xy(x+5)(4x−1)

Step-by-step explanation:

1 Find the Greatest Common Factor (GCF).

GCF = 2xy

2 Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

2xy (8x^3y + 38x^2y/2xy + −10xy/2xy)

3 Simplify each term in parentheses.

2xy(4x^2 +19x−5)

4 Split the second term in 4x^2+19x-5 into two terms.

2xy(4x^2 +20x−x−5)

5 Factor out common terms in the first two terms, then in the last two terms.

2xy(4x(x+5)−(x+5))

6 Factor out the common term x+5.

2xy(x+5)(4x−1)

7 0
2 years ago
If g(x)=4x^2-16 we’re shifted 9 united to the right and 1 down, what would the new equation be?
Inessa05 [86]

Shown in the graph

<h2>Explanation:</h2>

Using graph tools we can graph the function:

g(x)=4x^2-16

which is the red graph shown below. As you can see, this is a parabola. The rule for vertical and horizontal shifts is as follows:

Let \ c \ be \ a \ positive \ real \ number. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:

\bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ h(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ h(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ right \ \mathbf{right}: \\ h(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ left \ \mathbf{left}: \\ h(x)=f(x+c)

Therefore, If we shift the red graph 9 units to the right and 1 down, our new function (let's call it h(x)) will be:

h(x)=4\left(x-9\right)^{2}-16-1 \\ \\ Simplifying: \\ \\ h(x)=4\left(x-9\right)^{2}-17

This graph is the blue graph below. Let's verify the transformation taking the vertex of the red graph:

(0,-16)

By translating the 9 units to the right and 1 down the vertex is also translated by the same rule, so:

New \ vertex: \\ \\ (0+9,-16-1) \\ \\ (9,-17)

<h2>Learn more:</h2>

Cubic function: brainly.com/question/13773618#

#LearnWithBrainly

5 0
3 years ago
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