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3 years ago

13

A family uses 15 gallons of milk every 3 weeks. At that rate, about how many gallons of milk will they need to purchase in a yea

r’s time?
Give your answer as a whole number.
ONLY ANSWER IF YOU KNOW THE ANSWER

1 answer:

saw5 [17]3 years ago

8 0

Answer:

87 gallons

Step-by-step explanation:

5 gallons: 3 weeks = x gallons: 52 weeks

5/3 = x/52

3x = 260

x= 86.6, about 87 gallons

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how do I solve 7v-(2v-16)=5(v+4) please explain if it is a one solution, no solution or infinite solution

Sergio039 [100]

Do the indicated mult. first:

7v - 2v + 16 = 5v + 20
5v + = 5v +20. This is never true. NO solution.

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3 years ago

Cos(-170°) = _____<br><br> -cos10°<br> cos10°<br> cos(-10°)

ikadub [295]

<em>The right answer for:</em>

<em>cos(-170°) = _____</em>

<em>is:</em>

<em>-cos10°</em>

<h2>Explanation:</h2>

The cosine function is an even function, which means that for every point $(x,y)$ on the graph of $y=cos(x)$ then the point $(-x,y)$ also lies on the graph of the function. In other words, we can write:

$cos(-170^{\circ})=cos(170^{\circ})$

But:

$170^{\circ}=180^{\circ}-10^{\circ}$

So:

$cos(170^{\circ})=cos(180^{\circ}-10^{\circ})$

By property:

$cos(a-b)=cosacosb+sinasinb \\ \\ a=180^{\circ} \\ \\ b=10^{\circ} \\ \\ cos(170^{\circ} )=cos(180^{\circ} -10^{\circ})=cos180^{\circ} cos10^{\circ} +sin180^{\circ} sin10^{\circ} \\ \\ cos(170^{\circ})=-cos(10^{\circ})+0 \\ \\ \boxed{cos(170^{\circ})=-cos(10^{\circ})}$

<h2>Learn more:</h2>

Trigonometric functions: brainly.com/question/2680050

#LearnWithBrainly

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3 years ago

Use the distributive parenthesis: 7(m + 9)<br> will give brainliest if answered correctly!

Phantasy [73]

Answer:

The simplified answer would be 7m+63. You would have to solve for the variable.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Consider a uniform distribution from aequals4 to bequals29. (a) Find the probability that x lies between 7 and 27. (b) Find th

weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

$P(c \leq x \leq d) = \frac{d - c}{b - a}$

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So $c = 7, d = 27$

$P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8$

80% probability that x lies between 7 and 27.

(b) Find the probability that x lies between 6 and 13. 

So $c = 6, d = 13$

$P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28$

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

So $c = 9, d = 20$

$P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44$

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So $c = 11, d = 18$

$P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28$

28% probability that x lies between 11 and 18.

3 0

2 years ago

Use the image below to answer the following question. Find the value of sin x° and cos y°. What relationship do the ratios of si

Inessa [10]

Using relations in a right triangle, it is found that:

$\sin{x} = \frac{6}{10} = 0.6$

$\cos{y} = \frac{6}{10} = 0.6$

Since x and y are complementary angles, we have that sin(xº) = cos(yº).

<h3>What are the relations in a right triangle?</h3>

The relations in a right triangle are given as follows:

The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.

The cosine of an angle is given by the length of the adjacent side to the angle divided by the length of the hypotenuse.

The tangent of an angle is given by the length of the opposite side to the angle divided by the length of the adjacent side to the angle.

The hypotenuse in this problem is given as follows:

$h^2 = 6^2 + 8^2$

$h = \sqrt{100}$

h = 10.

The sine of x is:

$\sin{x} = \frac{6}{10} = 0.6$

The cosine of y is:

$\cos{y} = \frac{6}{10} = 0.6$

Since x and y are complementary angles, we have that sin(xº) = cos(yº).

More can be learned about relations in a right triangle at brainly.com/question/26396675

#SPJ1

8 0

2 years ago