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Nutka1998 [239]
3 years ago
8

9/16= what to the power of 2

Mathematics
1 answer:
Damm [24]3 years ago
3 0
The answer to this is 3/4.
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This is the graph of y=x^2+2x-2 what is the range of this function
Sedaia [141]
The range is [-3, ∞)
3 0
3 years ago
Simplify the cube root in simplest radical form.<br> 9x374<br> Please help
algol [13]

Answer:

D. xy\sqrt[3]{9y}

Step-by-step explanation:

\sqrt[3]{9x^3y^4}

\sqrt[3]{9}\sqrt[3]{x^3}\sqrt[3]{y^4}

The \sqrt[3]{x^3} cancels out to become x:

\sqrt[3]{9}x\sqrt[3]{y^4}

Split the y^4=y*y^3

\sqrt[3]{9}x\sqrt[3]{y^3}\sqrt[3]{y^1}

\sqrt[3]{y^3} =y

xy\sqrt[3]{9} \sqrt[3]{y}

Put the cube root of y and cube root of 9 together:

xy\sqrt[3]{9y}

6 0
3 years ago
What is the range of f(x)=-3^x+4
Mice21 [21]
The range is [4,∞)
Or from 4 to positive infinity
Or y is greater than or equal to 4
5 0
3 years ago
I need help plzz
sesenic [268]

Answer:

3200

Step-by-step explanation:

8 0
3 years ago
Checkpoint Quiz 1<br> 1. Write a formula for finding the area of a parallelogram.<br> le
azamat

Answer:

The formula for area of a parallelogram is either A=bh or A=\dfrac{d_1d_2}{2}.

Step-by-step explanation:

If base and vertical height of a parallelogram are given, then the area of the parallelogram is:

A=bh

Where, <em>b</em> is base and <em>h</em> is the vertical height of the parallelogram.

If measures of both diagonals are given, then the area of the parallelogram is:

A=\dfrac{d_1d_2}{2}

Where, d_1,d_2 are the two diagonals of the parallelogram.

5 0
2 years ago
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