All categories

2 years ago

I think it’s 393.75 But not Sure can anyone confirm ? Or share the right answer

Mathematics

1 answer:

Naya [18.7K]2 years ago

5 0

Answer:

$415.63

Step-by-step explanation:

it would have been 393.75, but he worked 5 hours overtime and got paid time and a half for it, meaning his normal pay plus half of it. (only for overtime tho).

so first calculate his normal pay:

40 × 8.75 = 350

then add overtime to it

8.75 × 5 = 43.75

43.75 × 1.5 = 65.625

65.625 + 350 = 415.625

round that and its 415.63!

You might be interested in

<img src="https://tex.z-dn.net/?f=I%20need%20help%20can%20someone%20help%3F%20I%E2%80%99m%20really%20stuck%20and%20it%E2%80%99s%

Dovator [93]

The pictures are blurry I can’t see anything

3 0

2 years ago

Darcy uses place value blocks to show a number. She uses 4 thousand blocks and five hundereds blocks. What is the number? How ca

Maksim231197 [3]

Answer is 4,500. 4 1,000 blocks =4,000. 5x100 =500. 4,000 + 500 = 4,500.

4 0

3 years ago

What is the volume? 7 cm 5 cm 8 cm cubic centimeters

Flura [38]

Answer:

280 cm

or 280cm^2

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Which of the following is true about the solution to h - 9 = 1?

Fed [463]

The solution must be larger than 9, because the answer is h=10

8 0

2 years ago

A 90% confidence interval for the mean height of students

Westkost [7]

Answer:

$ME= \frac{69.397-60.128}{2}= 4.6345 \approx 4.635$

And the best answer on this case would be:

b) m = 4.635

Step-by-step explanation:

Let X the random variable of interest and we know that the confidence interval for the population mean $\mu$ is given by this formula:

$\bar X \pm t_{\alpha/2} \frac{s}{\sqrt{n}}$

The confidence level on this case is 0.9 and the significance $\alpha=1-0.9=0.1$

The confidence interval calculated on this case is $60.128 \leq \mu \leq 69.397$

The margin of error for this confidence interval is given by:

$ME =t_{\alpha/2} \frac{s}{\sqrt{n}}$

Since the confidence interval is symmetrical we can estimate the margin of error with the following formula:

$ME = \frac{Upper -Lower}{2}$

Where Upper and Lower represent the bounds for the confidence interval calculated and replacing we got:

$ME= \frac{69.397-60.128}{2}= 4.6345 \approx 4.635$

And the best answer on this case would be:

b) m = 4.635

4 0

2 years ago