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4 years ago

Over what interval is the function in this graph decreasing

Mathematics

2 answers:

posledela4 years ago

6 0

C)

you look at were the graph starts to decrease then look at the X-VALUE not the y-value

the x-val at the start of the decrease is -3 and at the end of it it is 2 therefor -3 $\leq$ x $\leq$ 2

Furkat [3]4 years ago

5 0

Answer: C is the answer look at the picture for reference

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Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if n = 100.

(2) A Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable X following a Binomial distribution with parameters n and p.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if n = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

8 0

3 years ago

A tortoise and a hare are competing in a race around a 1600-meter track. The arrogant hare decides to let the tortoise have a 78

Sindrei [870]

I am presuming that the question is who won or by how much did the winner win.

distance equals rate times time, or d = r*t
For the Hare d = 1600 and r = 10
1600 = 10 t
Divide both sides by 10
t = 160
The hare finished in 160 seconds

For the tortoise d = 1600 - 780 = 820 (due to the head start) and r = 5.3
820= 5.3 t
Divide both sides by 5.3
t = 154.72 (rounded to the hundredths place)

The tortoise won by 5. 28 seconds (160-154.72)

6 0

3 years ago

Read 2 more answers

A farmer planned to plant 120 seeds in all. After planting 10 more seeds each day than was planned, she was able to finish 2 day

zheka24 [161]

Let s=number of seeds and t=number of days...

st=120 and (s+10)(t-2)=120

From the first we can say t=120/s, now using this value of t in the second equation gives us:

(s+10)(120/s-2)=120

(s+10)(120-2s)/s=120

(s+10)(120-2s)=120s

120s-2s^2+1200-20s=120s

2s^2+20s-1200=0

s^2+10s-600=0

(s+30)(s-20)=0, since s>0

s=20, and since she planted s+10 seeds per day to finish two days earlier:

20+10=30

She planted 30 seeds per day.

3 0

3 years ago

Evaluate the function at the given values F(y) = 4y^4 - 6y^2 + 8y - 15 At y = 2

otez555 [7]

F(2)= 4(16) - 6(4) + 8(2) - 15
F(2)= 64 -24 + 16 - 15
F(2)= 41

7 0

3 years ago

An item that is on sale for 40% off costs $66. What was the item's regular price?

IRINA_888 [86]

Answer:

The regular price was $110

Step-by-step explanation:

Hi there !

60% .......... $66

100% ..........$ x

x = 100×66/60

= 6600/60

= $ 110

Good luck !

7 0

3 years ago