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julsineya [31]
3 years ago
9

6 people meet for a business lunch. Each person shakes hands once with each other person present. How many handshakes take place

?
Mathematics
2 answers:
GalinKa [24]3 years ago
7 0
First\ person-5\ shakes\ hands\\Second\ person-4\ shakes\ hands\\3-th\ person-3\ shakes\ hands\\4-th\ person-2\ shakes\ hands\\5-th\ person-1\ shakes\ hands\\\\1+2+3+4+5=15\ \ shakes\ hands
schepotkina [342]3 years ago
5 0
1+2+3+4+5=15
There will be 15 handshakes :)
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HW 7.4/7.5 help mhhhh
Hatshy [7]

Answer:

1. LI=18

2. x=10

3. Yes (Y)

4. Yes (Y)

5. x=15

6. x=18

7. x=8

8. x=6

   y=6.5

Step-by-step explanation:

1. LI/JL=KH/JK

Replacing the given values:

LI/6=21/7

Dividing on the right side of the equation:

LI/6=3

Solving for LI: Multiplying both sides of the equation by 6:

6(LI/6)=6(3)

LI=18


2.TV/VS=RU/US

Replacing the given values:

x/17.5=8/14

Simplifying the fraction on the right side of the equation: Dividing numerator and denominator by 2:

x/17.5=(8/2) / (14/2)

x/17.5=4/7

Solving for x: Multiplying both sides of the equation by 17.5:

17.5(x/17.5)=17.5(4/7)=(17.5/1)(4/7)

Multiplying:

x=(17.5 x 4) / (1 x 7)

x=70/7

Dividing:

x=10


3. BC is parallel to DE if AD/DB is equal to AE/EC:

AD/DB=15/12=(15/3) / (12/3)→AD/DB=5/4

AE/EC=10/8=(10/2) / (8/2)→AE/EC=5/4

Like AD/DB=5/4=AE/EC → BC is parallel to DE


4. BC is parallel to DE if AD/DB is equal to AE/EC:

AD/DB= 2DB / DB→AD/DB=2

AE/EC=30 / (AC-AE)=30 / (45-30)=30/15→AE/EC=2

Like AD/DB=2=AE/EC → BC is parallel to DE


5. If JH is a midsegment of triangle KLM:

x=(1/2)(30)

x=15


6. If JH is a midsegment of triangle KLM:

x=2(9)

x=18


7. If JH is a midsegment of triangle KLM: x=8


8. 2x+1=x+7

Solving for x. Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

2x+1-x=x+7-x

Subtracting:

x+1=7

Subtracting 1 both sides of the equation:

x+1-1=7-1

Subtracting:

x=6

2x+1=2(6)+1=12+1→2x+1=13

x+7=6+7→x+7=13


(3y-8)/(y+5)=(2x+1)/(x+7)

(3y-8)/(y+5)=13/13

(3y-8)/(y+5)=1

3y-8=y+5

Solving for y. Grouping the y's on the left side of the equation: Subtracting y both sides of the equation:

3y-8-y=y+5-y

Subtracting:

2y-8=5

Adding 8 both sides of the equation:

2y-8+8=5+8

Subtracting:

2y=13

Dividing both sides of the equation by 2:

2y/2=13/2

Dividing:

y=6.5



3 0
3 years ago
How many 2/3 's make up 4 1/5
miskamm [114]

Answer:

6³/₁₀

Step-by-step explanation:

Number of bits = Total amount/Size of each bit

                         = (4⅕)/(⅔)

Convert the mixed number to an improper fraction

No. = (²¹/₅)/(⅔)

Invert the denominator and change division to multiplication

No. = ²¹/₅ × ³/₂

Multiply numerators and denominators.

No. = ⁶³/₁₀

Convert the improper fraction to a mixed number.

No. = 6³/₁₀

It takes 6³/₁₀ ⅔s to make up 4⅕.

3 0
2 years ago
There were 532 people at the Nutcracker. If admission was $24 for adults and $16 for children and $10,272 was collected, how man
anzhelika [568]
X = # adults

y = # children


system

24x+16y=$10272
x + y =532

4 0
3 years ago
Simplify using the vertical method. (3k + 4)(3k^2 – 5k – 3)
liubo4ka [24]

Answer:

9k^{3} -3k^{2}-29k-12

Step-by-step explanation:

Step 1: Expand by distributing sum groups.

3k(3k^{2} -5k-3)+4(3k^{2} -5k-3)

Step 2: Expand by distributing terms.

9k^{3} -15k^{2} -9k+4(3k^{2} -5k-3)

Step 3: Expand by distributing terms.

9k^{3}-15k^{2} -9k+12k^{2} -20k-12

Step 4: Collect like terms.

9k^{3}+(-15k^{2}  +12k^{2} )+(-9k-20k)-12

Step 5: Simplify.

9k^{3} -3k^{2}-29k-12

3 0
3 years ago
A field is 3645 feet long.<br><br> What is the length of the field in yards?
Ilya [14]

Answer:

answer of this question is 12150

8 0
2 years ago
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