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3 years ago

Find TM if BM=7 (Answer quickly)

Mathematics

1 answer:

liubo4ka [24]3 years ago

7 0

Answer:

I think 5

Step-by-step explanation:

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5x+8/2=9 solve for x

aliina [53]

x=1
5x+8/2=5x+4
9-4= 5
So now you have 5x=5 divide both sides by 5. And you’ll have x=1

4 0

3 years ago

Read 2 more answers

Which of the lines, if any, are parallel

Oksana_A [137]

Answer:

Line b and c

Step-by-step explanation:

5 0

3 years ago

Denote the set below by set-builder notation, using x as the variable.

Temka [501]

Answer:

C. {x|x is an odd natural number between 1 and 67}

Step-by-step explanation:

B and C is also correct if the natural number is defined to be started with 1: positive integer,

but if it's defined to be non-negative real number then only C

7 0

3 years ago

A recent article in the paper claims that government ethics are at an all-time low. Reporting on a recent sample,

Vitek1552 [10]

Answer:

Probability that more than eight but fewer than 12 of the 20 constituents sampled believe their representative possesses low ethical standards is 0.417890.

Step-by-step explanation:

We are given that the paper claims that 43% of all constituents believe their representative possesses low ethical standards.

Suppose 20 of a representative's constituents are randomly and independently sampled.

The above situation can be represented through binomial distribution;

$P(X=r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 20 constituents

r = number of success = more than eight but fewer than 12

p = probability of success which in our question is probability that

all constituents believe their representative possesses low

ethical standards, i.e; p = 43%

Let X = Number of constituents who believe their representative possesses low ethical standards

So, X ~ Binom(n = 20 , p = 0.43)

Now, Probability that more than eight but fewer than 12 of the 20 constituents sampled believe their representative possesses low ethical standards is given by = P(8 < X < 12)

P(8 < X < 12) = P(X = 9) + P(X = 10) + P(X = 11)

= $\binom{20}{9} \times 0.43^{9} \times (1-0.43)^{20-9}+ \binom{20}{10} \times 0.43^{10} \times (1-0.43)^{20-10}+\binom{20}{11} \times 0.43^{11} \times (1-0.43)^{20-11}$

= $167960 \times 0.43^{9} \times 0.57^{11}+ 184756 \times 0.43^{10} \times 0.57^{10}+167960 \times 0.43^{11} \times 0.57^{9}$

= 0.417890

Hence, the required probability is 0.417890.

7 0

3 years ago

The cafeteria serves pizza every 10 days and corn every 4 days. If they are serving pizza and corn today, in how many days will

alisha [4.7K]

Answer:

Well it would be 100 days

Step-by-step explanation:

Because they had pizza every ten days and if you add 5 days a week that's 50 days they sell pizza. If your talking corn they sell it every 4 days times 5 days a week that's 20 days of corn. Then you do 50 x 20 and then you get 100 days of pizza and corn, so it would be 100 days before they sell pizza and corn together again!

6 0

3 years ago