Answer:
Area of the shaded region = 23.33 in²
Step-by-step explanation:
Area of a sector =
Where θ = Central angle subtended by an arc
r = radius of the circle
Area of the sector BCD =
= 52.36 in²
Area of equilateral triangle BCD =
=
= in²
= 43.30 in²
Area of the shaded portion in ΔBCD = 52.36 - 43.3
= 9.06 in²
Area of sector CAD =
= 39.27 in²
Area of right triangle CAD =
=
=
= 25 in²
Area of the shaded part in the ΔACD = 39.27 - 25
= 14.27 in²
Area of the shaded part of the figure = 9.06 + 14.27
= 23.33 in²
One solution.
-20 divided by 5 is equal to -4. Unless both sides have the same number or one side has -=0 then it’s one solution
Hello, the correct answers are
truth for 0.25
false for 4
I just took quiz
18 kg of 15% copper and 72 kg of 60% copper should be combined by the metalworker to create 90 kg of 51% copper alloy.
<u>Step-by-step explanation:</u>
Let x = kg of 15% copper alloy
Let y = kg of 60% copper alloy
Since we need to create 90 kg of alloy we know:
x + y = 90
51% of 90 kg = 45.9 kg of copper
So we're interested in creating 45.9 kg of copper
We need some amount of 15% copper and some amount of 60% copper to create 45.9 kg of copper:
0.15x + 0.60y = 45.9
but
x + y = 90
x= 90 - y
substituting that value in for x
0.15(90 - y) + 0.60y = 45.9
13.5 - 0.15y + 0.60y = 45.9
0.45y = 32.4
y = 72
Substituting this y value to solve for x gives:
x + y = 90
x= 90-72
x=18
Therefore, in order to create 90kg of 51% alloy, we'd need 18 kg of 15% copper and 72 kg of 60% copper.
Answer:
Yes
Step-by-step explanation:
This equation is in slope-intercept form, . If graphed, it would be a line.
Hope this helps!